Answer:
A and D takes much slower
Explanation:
Here, we want to select, out of the four given reactions, the one that is slower than the other two
The answers in these case are reactions 1 and 4 ( A and D)
The two reactions show what is called rust (as directly seen in reaction 4)
When we speak of rust, we simply mean a reaction that occurs over time
For example, non coated roofings of houses doesn’t get to change color at an instant
The color degradation that occurs is something that takes some time from the initial time they were used to roof the house
Hence, from these analogy, we can see that these reactions need an an external support to thrive or to come into existence
These external supports are natural forces and they contributing efforts occur over time and cannot be seen immediately
These reactions are thus ones that take much slower time than conventional laboratory reactions in the case of the formation of the precipitate or a reaction that requires a low flash point temperature such as that of black powder to produce such explosive effects
So in conclusion, what we are saying is that the two selected reactions are subjected to the availability of some conditions and may take time to manifest and these absolutely differentiates them from reactions that are spontaneous such as the one having an explosive effect or the other one leading to the formation of a precipitate which takes far less times
If the electromagnetic radiation is travelling in vacuum, the velocity of the wave should be 3×10^8 m/s
Using the wave formula,
Velocity=wavelength×frequency,
frequency=(3×10^8)/(0.0107)
Answer:
Ba(OH)2(aq) + CO2(g) = BaCO3(s) + H2O(l)
Reaction type: double replacement
Explanation:
<u>Answer:</u> 185.66 grams of Lithium chloride must decompose.
<u>Explanation:</u>
To calculate the moles, we use the following equation:
![\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B%5Ctext%7BMolar%20mass%7D%7D)
Moles of Lithium:
Given mass of lithium = 30.3 grams
Molar mass of lithium = 6.91 g/mol
Putting values in above equation, we get:
![\text{Number of moles}=\frac{30.3g}{6.91g/mol}=4.38moles](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20moles%7D%3D%5Cfrac%7B30.3g%7D%7B6.91g%2Fmol%7D%3D4.38moles)
For the given chemical reaction, the equation follows:
![2LiCl\rightarrow 2Li+Cl_2](https://tex.z-dn.net/?f=2LiCl%5Crightarrow%202Li%2BCl_2)
By Stoichiometry of the reaction:
2 moles of lithium metal are produced by 2 moles of lithium chloride
So, 4.38 moles of lithium metal are produced by =
of lithium chloride.
Now, to calculate the mass of lithium chloride, we use the moles equation:
Molar mass of lithium chloride = 42.39 g/mol
Putting values in above equation, we get:
![4.38mol=\frac{\text{Given mass}}{42.39g/mol}](https://tex.z-dn.net/?f=4.38mol%3D%5Cfrac%7B%5Ctext%7BGiven%20mass%7D%7D%7B42.39g%2Fmol%7D)
Mass of lithium chloride = 185.66 grams
Hence, Mass of lithium chloride decomposed is 185.66 grams.
The balanced equation for the above reaction is as follows
CaCO₃ + 2HBr ---> CaBr₂ + CO₂ + H₂O
stoichiometry of CaCO₃ to HBr is 1:2
number of moles of CaCO₃ reacted - 5.64 g / 100 g/mol = 0.0564 mol
according to molar ratio
number of HBr moles - 0.0564 mol x 2 = 0.1128 mol
number of HBr moles in 250.0 mL - 0.1128 mol
therefore number of HBr moles in 1000 mL - 0.1128 mol / 250.0 mL x 1000 mL = 0.4512 mol
molarity of HBr - 0.4512 M