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mr Goodwill [35]
3 years ago
15

For the reaction, 2A + B → 3C, rate of disappearance of A is 0.3 M/s in a certain time interval.What is the average rate of appe

arance of C and what is the average rate of the reaction in that time interval?
A) rate of appearance of C = 0.45 M/s
rate of the reaction = 0.6 M/s
B) rate of appearance of C = 0.2 M/s
rate of the reaction = 0.6 M/s
C) rate of appearance of C = 0.2 M/s
rate of the reaction = 0.15 M/s
D) rate of appearance of C = 0.45 M/s
rate of the reaction = 0.3 M/s
E) rate of appearance of C = 0.45 M/s
rate of the reaction = 0.15 M/s
Chemistry
1 answer:
andrezito [222]3 years ago
7 0

Answer:

E) rate of appearance of C = 0.45 M/s

rate of the reaction = 0.15 M/s

Explanation:

2A + B → 3C

Writing rate law for the reaction:

<u>Rate of reaction</u> = -\frac{1}{2}\frac{d[A]}{dt} = -\frac{d[B]}{dt} = \frac{1}{3}\frac{d[C]}{dt} → equation 1

Given that the rate of disappearance of A is 0.3 M/s

⇒ - \frac{d[A]}{dt} = 0.3 M/s

⇒Rate of reaction = - \frac{1}{2}\frac{d[A]}{dt} = \frac{1}{2}×0.3 M/s

⇒<u>Rate of reaction = 0.15 M/s</u>

From equation 1, \frac{d[C]}{dt} = - \frac{3}{2}\frac{d[A]}{dt} = \frac{3}{2}×0.3 M/s

⇒\frac{d[C]}{dt} = 0.45 M/s

or <u>the rate of appearance of C = 0.45 M/s</u>

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