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vredina [299]
3 years ago
5

If a 12oz can of Soda contains 48.0g of sugar and you drink one can a day for one month (31 days), how many pounds (lb) of sugar

have you consumed from the soda alone? If 50% of this sugar is in the form of glucose (C6H12O6) how many grams of carbon have you consumed from glucose in the beverage over the 31 days?
Chemistry
1 answer:
marishachu [46]3 years ago
3 0

Answer:

yo dude on my questin can u answer my coment

Explanation:

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Why is water considered the greatest solvent on earth
kotykmax [81]
1) H2O is able to dissolve both polar molecules and non polar ones
2) due to its extreme polarity it can even dissolve some I onic compounds
3 the h2o molecule itself is small in size
6 0
4 years ago
Infer why the brown marmarated stink bug (BMSB) is an invasive species in the United States.
Anna71 [15]

Answer:

A. China And Japan.

Explanation:

The species is native to China/Japan and was introduced into the United States in the mid-1990s, possibly stowing away in a shipping container. The presence of this stink bug is concerning for farmers because it feeds on a large number of high-value crops and ornamental plants in its immature and adult life stages.

3 0
2 years ago
How many moles of CaCO3 are there for every two moles of HCl?
vlada-n [284]

Answer:

caco3ertyuio;lkjhgfdsxcvbnm,.

Explanation:

6 0
3 years ago
The average density of a carbon-fiber-epoxy composite is 1.615 g/cm3. the density of the epoxy resin is 1.21 g/cm3 and that of t
ra1l [238]
The composite material is composed of carbon fiber and epoxy resins. Now, density is an intensive unit. So, to approach this problem, let's assume there is 1 gram of composite material. Thus, mass carbon + mass epoxy = 1 g.

Volume of composite material = 1 g / 1.615 g/cm³ = 0.619 cm³
Volume of carbon fibers = x g / 1.74 g/cm³ 
Volume of epoxy resin = (1 - x) g / 1.21 g/cm³ 

a.) V of composite = V of carbon fibers + V of epoxy resin
0.619 = x/1.74 + (1-x)/1.21
Solve for x,
x = 0.824 g carbon fibers
1-x = 0.176 g epoxy resins

Vol % of carbon fibers = [(0.824/1.74) ÷ 0.619]*100 =<em> 76.5%</em>

b.) Weight % of epoxy = 0.176 g epoxy/1 g composite * 100 = <em>17.6%</em>
     Weight % of carbon fibers = 0.824 g carbon/1 g composite * 100 = <em>82.4%</em>
4 0
3 years ago
How many grams are there in 7.40 moles of AgNO3
malfutka [58]

Answer:

169.87 grams

Explanation:

4 0
3 years ago
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