Percentage of isotopes in 35/17 Cl and 37/17 Cl with the molar mass of chlorine as 35.5g and the mass of each nucleon to be 1.00
1 answer:
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The volume of concentrated HCl : 2.073 ml
<h3>Further explanation</h3>Given
37% HCl by mass; density 1.19 g/mL
Required
The volume of concentrated HCl
Solution
Conversion to molarity :
37% x 1.19 g/ml =0.4403 g/ml
g/ml to mol/L :
=0.4403 g/ml x 1000 ml/L : 36.5 g/mol
=12.06 mol/L
or we can use formula :
Dilution formula :
M₁V₁=M₂V₂
12.06 M x V₁ = 0.1 M x 0.25 L
V₁ = 0.0021 L = 2.073 ml
Answer:
0.396 M
Explanation:
Let's consider the following reaction.
2 COF₂(g) ⇌ CO₂(g) + CF₄(g)
We can find the concentrations at equilibrium using an ICE Chart.
2 COF₂(g) ⇌ CO₂(g) + CF₄(g)
I 2.00 0 0
C -2x +x +x
E 2.00-2x x x
The concentration equilibrium constant (Kc) is:
The concentration of COF₂ at equilibrium is:
[COF₂] = 2.00-2x = 2.00-2(0.802) = 0.396 M