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Westkost [7]
3 years ago
7

Percentage of isotopes in 35/17 Cl and 37/17 Cl with the molar mass of chlorine as 35.5g and the mass of each nucleon to be 1.00

00 amu
Chemistry
1 answer:
AlekseyPX3 years ago
4 0

Answer:

The abundance of 35/17 Cl is 75% and 25% of 37/17Cl

Explanation:

The molar mass of an atom is defined as the sum of the masses of each isotope times its abundance, that is:

35.5amu = 35amu*X + 37amu*Y <em>(1)</em>

<em>Where X is the abundance of the 35/17Cl and Y the abundance of 37/17 Cl</em>

<em />

As there are just these 2 isotopes and the abundances of both isotopes = 1:

X + Y = 1 <em>(2)</em>

<em></em>

Replacing (2) in (1):

35.5 = 35X + 37(1-X)

35.5 = 35X + 37 - 37X

-1.5 = -2X

X = 0.75 = 75%

And Y = 100-75% = 25%

<h3>The abundance of 35/17 Cl is 75% and 25% of 37/17Cl</h3>
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Here it is how to solve.
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