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2 years ago

A bottle holds 24 ounces of water. It has x ounces of water in it. What does 24 - x represent in the situation?

Mathematics

2 answers:

Misha Larkins [42]2 years ago

4 0

It represents the ounces of water that the bottle can still hold.

fredd [130]2 years ago

4 0

I represents the amount of water the bottle could hold, but does not currently have in it. (Aka the amount of space in the bottle, in terms of oz or water)

I hope this helps!

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Answer:

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Step-by-step explanation:

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2 years ago

Your parents took your family out to dinner. Your parents wanted to give the waiter a 15% tip. If the total amount of the dinner

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$48.30

Step-by-step explanation:

If the dinner was $42.00 and they wanted to give a 15% tip, then to find that start by multiplying 42 by 0.15

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now add $6.30 to $42.00

42 + 6.3 = 48.3

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Answer:b

Step-by-step explanation:

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2 years ago

Work out the surface area of a cylinder when the height = 18cm and the volume = 1715cm cubed

lara [203]

Answer:

813.4 cm² (nearest tenth)

Step-by-step explanation:

Volume of a cylinder

$\sf V=\pi r^2 h \quad\textsf{(where r is the radius and h is the height)}$

Given:

h = 18cm
V = 1715 cm³

Use the Volume of a Cylinder formula and the given values to find the radius of the cylinder:

$\implies \sf 1715=\pi r^2 (18)$

$\implies \sf r^2=\dfrac{1715}{18 \pi}$

$\implies \sf r=\sqrt{\dfrac{1715}{18 \pi}$

Surface Area of a Cylinder

$\sf SA=2 \pi r^2 + 2 \pi r h \quad\textsf{(where r is the radius and h is the height)}$

Substitute the given value of h and the found value of r into the formula and solve for SA:

$\implies \sf SA=2 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)^2 + 2 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)(18)$

$\implies \sf SA=2 \pi \left(\dfrac{1715}{18 \pi} \right) + 36 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)$

$\implies \sf SA=\dfrac{1715}{9} + 36 \pi \left(\sqrt{\dfrac{1715}{18 \pi}\right)$

$\implies \sf SA=813.3908956...$

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1 year ago

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harkovskaia [24]

Answer:

Step-by-step explanation:

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Therefore, E is the correct option.

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