3 years ago

It takes five hours to drive from Fort Worth to Midland, which is a distance of 300 miles. What

Physics

1 answer:

Shkiper50 [21]3 years ago

8 0

Answer:

Explanation:

(hint: speed = distance/time)

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A ball is dropped from a height of 4.6 meters above the ground. What is the impact

Semenov [28]

Answer: 14m/s

Explanation:

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2 years ago

An Earth satellite moves in a circular orbit 561 km above Earth's surface with a period of 95.68 min. What are (a) the speed and

crimeas [40]

Explanation:

It is given that,

Radius of earth, r = 6371 km

An earth satellite moves in a circular orbit above the Earth's surface, d = 561 km

So, radius of satellite, R = 6371 km + 561 km = 6932 × 10³ m

Time taken, t = 95.68 min = 5740.8 sec

(a) Speed of the satellite is given by :

$v=\dfrac{d}{t}$

d = distance covered

For circular path, d = 2πR

$v=\dfrac{2\pi \times 6932\times 10^3\ m}{5740.8\ sec}$

v = 7586.92 m/s

(b) Centripetal acceleration is given by :

$a=\dfrac{v^2}{R}$

$a=\dfrac{(7586.92\ m/s)^2}{6932\times 10^3\ m}$

$a=8.3\ m/s^2$

Hence, this is the required solution.

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4 years ago

Stars that are closer look— A. brighter B. dimmer C. white

Luba_88 [7]

The answer is A. Brighter

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3 years ago

Read 2 more answers

A sample of gold has a mass of 30.94 grams and density of 19.32g/cm^3. What volume of space will this sample of gold occupy?

sdas [7]

Data:
mass, m = 30.94 g
density, d = 19.32 g/cm^3

Formula: d = m / v => v = m / d = 30.94 g / 19.32 g/cm^3 = 1.60 cm^3

Then, the answer is the option C.

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3 years ago

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For a certain RLC circuit the maximum generator EMF is 125 V and the maximum current is 3.20 A. If le a) the impedance of the ci

MAXImum [283]

Answer:

Part (i)

Z = 39.06 ohm

Part (ii)

R = 21.7 ohm

Explanation:

a) here we know that

maximum value of EMF = 125 V

maximum value of current = 3.20 A

now by ohm's law we can find the impedence as

$z = \frac{V_o}{i_o}$

now we will have

$z = \frac{125}{3.20} = 39.06 ohm$

Part b)

Now we also know that

$\frac{R}{z} = cos\theta$

$\theta = 0.982 rad = 56.3 degree$

now we have

$\frac{R}{39.06} = cos56.3$

$R = 21.7 ohm$

5 0

3 years ago