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MakcuM [25]
3 years ago
10

What is newton's third law second law first law ?​

Physics
2 answers:
sergeinik [125]3 years ago
8 0

Answer:

first law: an object remains in uniform motion except an external force has acted upon it eg a ball in stable motion doesn't move until one moves or kicks it

second law:the body acted upon by an external force gains a momentum which is directly proportional to the applied force and acts in the direction of the force

third law: to every action there is an equal and opposite reaction eg if u push someone the person moves backward away from you and not towards you

fgiga [73]3 years ago
8 0

Answer:

Newton's Second law of motion: "Force = mass × acceleration."

Newton's Third law of motion: "Every action has an equal and opposite reaction."

Explanation:

An example of Newton's third law is when a rocket is launched, the boosters apply force on the ground and the ground pushes back, which makes the rocket take off.

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As a train accelerates away from a station, it reaches a speed of 4.6 m/s in 5.2 s. If the train's acceleration remains constant
Svet_ta [14]

Answer:

Vf = 10.76 m/s

Explanation:

Train kinematics

The train moves with uniformly accelerated movement

V_f = V_o + a*t Formula (1)

Vf: Final speed (m/s)

V₀: Inital speed (m/s)

t: time in seconds (s)

a: acceleration (m/s²)

Movement from t = 0 to t = 5.2s

We replace in formula (1)

4.6 = 0 + a*5.2

a = 4.6/5.2 = 0.88 m/s²

Movement from t = 5.2s to t = 5.2s + 7s = 12.2s

We replace in formula (1)

V_f = 4.6 + 0.88*7

Vf = 10.76 m/s

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3 years ago
Cause and Effect :
bazaltina [42]

Answer:

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7 0
3 years ago
Read 2 more answers
Please help ASAP.
Elden [556K]

Answer:

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8 0
3 years ago
PLEASE HELP WILL GIVE BRAINLEST!!!
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Answer:

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Explanation:

3 0
3 years ago
The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be
kap26 [50]

Answer:

v = 14.86 m/s

Explanation:

As we know that the force equation at the top is given as

\frac{mv^2}{R} = ma

now we know that

a_c = 1.5 g

so we have

\frac{v^2}{R} = 1.5 g

v = \sqrt{1.5 Rg}

so we will have

v = \sqrt{1.5(15)(9.81)}

v = 14.86 m/s

3 0
3 years ago
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