<h2>
82.353 km/hr</h2>
Explanation:
The driver travels 135 km towards East in 1.5 hr. He stops for 45 min. He again travels 215 km towards East in 2.0 hr.
The total displacement of the driver in the given time is ths sum of individual displacements, because all the displacements are in the same directon.
Total displacement = 
Total time travelled = 
∴ Driver's average velocity = 
The answer is 24N. Since the body is moving with constant velocity all the forces must balance (equal & opposite)
The electric field strength of a point charge is inversely proportional to the square of the distance from the charge ... a lot like gravity.
If the magnitude of the field is (2E) at the distance 'd', then at the distance '2d', it'll be (2E)/(2²). That's (2E)/4 = 0.5E .
Answer:
Approximate height of the building is 23213 meters.
Explanation:
Let the height of the building be represented by h.
0.02 radians = 0.02 × 
= 0.02 x (180/
)
0.02 radians = 1.146°
10.5 km = 10500 m
Applying the trigonometric function, we have;
Tan θ = 
So that,
Tan 1.146° = 
⇒ h = Tan 1.146° x 10500
= 2.21074 x 10500
= 23212.77
h = 23213 m
The approximate height of the building is 23213 m.
Its C. 66 cal , that's your answer to your question.
