Answer:
![\boxed {\boxed {\sf 40 \ kilograms}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%2040%20%5C%20kilograms%7D%7D)
Explanation:
Momentum is the product of velocity and mass. The formula is:
![p=m*v](https://tex.z-dn.net/?f=p%3Dm%2Av)
We know the rock is falling. Its momentum is 200 kilograms meters per second and its velocity is 5 meters per second. Substitute the values into the formula.
![200 \ kg \ m/s = m * 5.0 \ m/s](https://tex.z-dn.net/?f=200%20%5C%20kg%20%5C%20m%2Fs%20%3D%20m%20%2A%205.0%20%5C%20m%2Fs)
We are solving for m, the mass. We must isolate the variable. It is being multiplied by 5 meters per second. The inverse of multiplication is division, so we divided both sides by 5.0 m/s.
![\frac{200 \ kg \ m/s}{5.0 \ m/s}=\frac{ m* 5.0 \ m/s }{5.0 \ m/s}](https://tex.z-dn.net/?f=%5Cfrac%7B200%20%5C%20kg%20%5C%20m%2Fs%7D%7B5.0%20%5C%20m%2Fs%7D%3D%5Cfrac%7B%20m%2A%205.0%20%5C%20m%2Fs%20%7D%7B5.0%20%5C%20m%2Fs%7D)
![\frac{200 \ kg \ m/s}{5.0 \ m/s}=m](https://tex.z-dn.net/?f=%5Cfrac%7B200%20%5C%20kg%20%5C%20m%2Fs%7D%7B5.0%20%5C%20m%2Fs%7D%3Dm)
The units of meters per second (m/s) cancel.
![\frac{200 \ kg}{5.0 } =m](https://tex.z-dn.net/?f=%5Cfrac%7B200%20%5C%20kg%7D%7B5.0%20%7D%20%3Dm)
![40 \ kg = m](https://tex.z-dn.net/?f=40%20%5C%20kg%20%3D%20m)
The falling rock has a mass of <u>40 kilograms.</u>
Answer:
F.
Explanation:
Here in the question the mass of the pulley is zero, hence, the tension in the cable throughout is same.
magnitude of tension in rope 1 is
T1= F
Hence the tension T1 is rope 1 is F.
Car with a mass of 1210 kg moving at a velocity of 51 m/s.
2. What velocity must a 1340 kg car have in order to have the same momentum as a 2680 kg truck traveling at a velocity of 15 m/s to the west? 3.0 X 10^1 m/s to the west.
Hope i helped
Have a good day :)
Answer:
s is distance so it's dimensions become L.
Nd other side we have ut+1\2at^2.
as 1\2 is a constant it will have dimensions and apply the dimensions to other quantities.
on solving u will get L there also i,e ur LHS = RHS.
thus the equation is dimensionally consistent.
Explanation:
Answer:
When displacement is zero, the particle may be at rest, therefore, distance travelled = 0.
Again, when displacement is zero, the final position matches with the initial position after some time, but the distance travelled will not be zero.