WORK = W=Fd. Because energy is the capacity to do work , we measure energy and work in the same units (N*m or joules). POWER (P) is the rate of energy generation (or absorption) over time:P = E/t. Power's SI unit of measurement is the Watt, representing the generation or absorption of energy at the rate of 1 Joule/sec.
The wise and careful use of energy is called CONSERVATION
Answer:
<u><em>note:</em></u>
<u><em>find the attached solution:</em></u>
consider the motion in Y-direction
v₀ = initial velocity = 29 Sin62 = 25.6 m/s
a = acceleration = - 9.8 m/s²
t = time of travel
Y = vertical displacement = - 0.89 m
using the equation
Y = v₀ t + (0.5) a t²
- 0.89 = (25.6) t + (0.5) (- 9.8) t²
t = 5.3 sec
consider the motion along the horizontal direction :
v₀ = initial velocity = 29 Cos62 = 13.6 m/s
a = acceleration = 0 m/s²
t = time of travel = 5.3 sec
X = horizontal displacement =?
using the equation
X = v₀ t + (0.5) a t²
X = (13.6) (5.3) + (0.5) (0) t²
X = 72.1 m
d = distance traveled by the center fielder to catch the ball = 107 - x = 107 - 72.1 = 34.9 m
t = time taken = 5.3 sec
v = speed of center fielder
using the equation
v = d/t
v = 34.9/5.3
v = 6.6 m/s
To solve the problem it is necessary to apply the concepts related to the voltage in a coil, through the percentage relationship that exists between the voltage and the number of turns it has.
So things our data are given by
PART A) Since it is a system in equilibrium the relationship between the two transformers would be given by
So the voltage for transformer 2 would be given by,
PART B) To express the number value we proceed to replace with the previously given values, that is to say
