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valina [46]
3 years ago
5

A baseball was thrown off of a 35 meter high building. It lands 50 meters from the base of the building.

Physics
1 answer:
shutvik [7]3 years ago
4 0

Wonderful.

Look out below !

Was the FAA notified ?

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When air is warm, it rises and leaves an area of low pressure which becomes filled with sinking cold air. After a hot, sunny day
expeople1 [14]
<span>Cool air from the shore will travel to the sea</span>
8 0
3 years ago
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Match the following terms,
stiv31 [10]

Answer:

1. heat engine ~~ •a machine that converts the internal energy of a fuel into mechanical energy.

2. heat pump ~~ •an appliance that extracts heat energy from one source and deposits it

elsewhere.

3. Boiler ~~ •a heating appliance that uses heat energy released from fossil fuels to warm water for use in radiant or

convection heating systems.

4. Thermostat ~~ •an appliance that controls the maintenance temperature of a heating

system

6 0
3 years ago
Two trains on separate tracks move toward each other. Train 1 has a speed of 145 km/h; train 2, a speed of 72.0 km/h. Train 2 bl
tekilochka [14]

Answer:

Therefore,

The frequency heard by the engineer on train 1

f_{o}=603\ Hz

Explanation:

Given:

Two trains on separate tracks move toward each other

For Train 1 Velocity of the observer,

v_{o}=145\ km/h=145\times \dfrac{1000}{3600}=40.28\ m/s

For Train 2 Velocity of the Source,

v_{s}=90\ km/h=90\times \dfrac{1000}{3600}=25\ m/s

Frequency of Source,

f_{s}=500\ Hz

To Find:

Frequency of Observer,

f_{o}=?  (frequency heard by the engineer on train 1)

Solution:

Here we can use the Doppler effect equation to calculate both the velocity of the source v_{s} and observer v_{o}, the original frequency of the sound waves f_{s} and the observed frequency of the sound waves f_{o},

The Equation is

f_{o}=f_{s}(\dfrac{v+v_{o}}{v -v_{s}})

Where,

v = velocity of sound in air = 343 m/s

Substituting the values we get

f_{o}=500(\dfrac{343+40.28}{343 -25})=500\times 1.205=602.64\approx 603\ Hz

Therefore,

The frequency heard by the engineer on train 1

f_{o}=603\ Hz

7 0
3 years ago
How to get infinite thanks could you show me please ☺️​
murzikaleks [220]

Answer: divide by zero, or square root of a negative

Explanation: If your question is how to get infinity as an answer to a problem, that generally means that the answer is undefined or doesn't exist.

A couple of ways to get that...

  1. You try to divide by zero. In other words, a problem that asks you to perform something like this:  5/0=   or 23/(4-4)=   Such a problem will give you an error on a calculator because the answer is infinity or doesn't exist.
  2. Another way is to try to get the square root of a negative number. That answer doesn't exist as a real number, so \sqrt{-4\\} will also give you an error on a calculator.

7 0
3 years ago
In a local bar, a customer slides an empty beer mug down the counter for a refill. the height of the counter is 1.15 m. the mug
yarga [219]

<span>A.    </span>Let’s say the horizontal component of the velocity is vx and the vertical is vy. <span>
Initially at t=0 (as the mug leaves the counter) the components are v0x and v0y. 
<span>v0y = 0 since the customer slides it horizontally so applied force is in the x component only.

<span>The equations for horizontal and vertical projectile motion are:
x = x0 + v0x t 
y = y0 + v0y t - 1/2 g t^2 = y0 - 1/2 g t^2 </span></span></span>

Setting the origin to be the end corner of the counter so that x0=0 and y0=0, hence:

x = v0x t

y = - 1/2 g t^2 

Given value are: x=1.50m and y=-1.15m (y is negative since mug is going down)

<span>1.50m = v0x t    ---->  v0x= 1.50/t</span>

<span>-1.15m = -(1/2) (9.81) t^2    -----> t =0.4842 s</span>

Calculating for v0x:

v0x = 3.10 m/s

<span>B.    </span>v0x is constant since there are no other horizontal forces so, v0x=vx=3.10m/s

vy can be calculated from the formula:

<span>vy = v0y + at         where a=-g (negative since going down)</span>

vy = -gt = -9.81 (0.4842)

vy = -4.75 m/s

 

Now to get the angle below the horizontal, tan(90-Ø) = -vx/vy

tan(90-Ø )= 3.1/4.75

Ø = 56.87˚<span> below the horizontal</span>

4 0
4 years ago
Read 2 more answers
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