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givi [52]
4 years ago
7

The process of finding objects by emitting sounds and interpreting their reflections is called

Physics
1 answer:
ddd [48]4 years ago
8 0
Echolocation is the process of finding objects by emitting sounds and interpreting their reflections. This process uses echo. When sound is produced, it travels and hits an object. Sound bounces off the object and is reflected back. The echo produced helps to identify the location of the object and even size of the object. Echolocation is used by animals such as bats and dolphins to navigate and also hunt.
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When two objects made of different materials are rubbed together, they will attract each other after the charging process.Immers
Sergio039 [100]

Answer:

True

Explanation:

because their is friction(e.g take a ruler rub it in your hair then put it on top of a piece of paper on the table then u will see the process)among the two objects.

4 0
2 years ago
An example of a land feature formed by river erosion is?
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<span>There are various examples of land features formed by river erosion. One of them is Delta. A delta is formed when sediments are deposited in a place where a river flow into an ocean or lake and build up a land form. Thus, a river delta is a land form that occurs as a result of deposition of sediments carried by a river as the flow leaves its mouth and enter a slow moving or stagnant water.</span>
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3 years ago
Does the sign of the charge (positive or negative) affect how that charge is dissipated? Explain.
labwork [276]
This is an add proceeded by
5 0
3 years ago
Which type of mirror always has an image that is smaller than the object?
BaLLatris [955]

Which type of mirror always has an image that is smaller than the object?

convex

7 0
3 years ago
Read 2 more answers
A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The
Goshia [24]

Answer:

0.629\ \text{rad/s}^2 counterclockwise

9.98\ \text{s}

Explanation:

r_1 = Small drive wheel radius = 2.2 cm

\alpha_1 = Angular acceleration of the small drive wheel = 8\ \text{rad/s}^2

r_2 = Radius of pottery wheel = 28 cm

\alpha_2 = Angular acceleration of pottery wheel

As the linear acceleration of the system is conserved we have

r_1\alpha_1=r_2\alpha_2\\\Rightarrow \alpha_2=\dfrac{r_1\alpha_1}{r_2}\\\Rightarrow \alpha_2=\dfrac{2.2\times 8}{28}\\\Rightarrow \alpha_2=0.629\ \text{rad/s}^2

The angular acceleration of the pottery wheel is 0.629\ \text{rad/s}^2.

The rubber drive wheel is rotating in clockwise direction so the pottery wheel will rotate counterclockwise.

\omega_i = Initial angular velocity = 0

\omega_f = Final angular velocity = 60\ \text{rpm}\times \dfrac{2\pi}{60}=6.28\ \text{rad/s}

t = Time taken

From the kinematic equations of linear motion we have

\omega_f=\omega_i+\alpha_2t\\\Rightarrow t=\dfrac{\omega_f-\omega_i}{\alpha_2}\\\Rightarrow t=\dfrac{6.28-0}{0.629}\\\Rightarrow t=9.98\ \text{s}

The time it takes the pottery wheel to reach the required speed is 9.98\ \text{s}

4 0
3 years ago
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