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2 years ago

Linda is a forensic scientist arriving at the crime scene. What must she do before she can examine the crime scene?

Physics

2 answers:

Bezzdna [24]2 years ago

7 0

Answer:

In the more scientific viewpoint, the most important thing that she must do is caring for her hygiene and put some plastic gloves in her hands.

This is because there are lots of particles that can be retained in the hands (dust, skin, etc), and when examining the scene, she may drop some of these particles, "contaminating" the scene in this way with information that only will affect the investigation.

So the most important thing is being prepared to not affect anything in the crime scene

pav-90 [236]2 years ago

3 0

Answer: Linda must first <u>secure the crime scene.</u>

Explanation:

Before examining the crime scene Linda must first secure the crime scene. By securing the crime scene bystanders will not be able to contaminate or hurt any evidence that could be used to help solve the case. This will also ensure the bystanders cannot hurt themselves on anything at the crime scene. This is necessary because evidence that is contaminated in any way can not be used in the case.

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A pan hangs from a 50 cm spring. When a 10 kg mass is placed in the pan, it stretches the spring 6 cm. What is a function rule l

MrRissso [65]

Answer:

Explanation:

A Spring stretches / compresses when force is applied on them and they are governed by the Hookes Law which states that the force required to stretch or compress a spring is directly proportional to the distance it is stretched.

$F = -kx$

F is the force applied and x is the elongation of the spring

k is the spring constant.

negative sign indicates the change in direction from equilibrium position.

In the given question, we dont have force but we know that the pan is hanging. We also know from the Newton's second law of motion that

$F=mg$

Inserting this into Hooke's Law

$mg=-kx$

computing it for x,

$-x=mg/k$

This is the model which will tell the length of the spring against change in the mass located in the pan.

3 0

2 years ago

If the car has a mass of 0.4 kg, the ratio of height to width of the ramp is 19/85, the initial displacement is 1.9 m, and the c

Rasek [7]

Answer:

final displacement lf = 0.39 m

Explanation:

from change in momentum equation:

$\delta p = m \sqrt(2g * y/x)* [\sqrt li + \sqrt lf]$

given: m = 0.4kg, y/x = 19/85, li = 1.9 m,

\delta p = 1.27 kg*m/s.

putting all value to get the final displacement value

$1.27 = 0.4\sqrt(2*9.81 *(19/85))* [\sqrt 1.9 + \sqrt lf]$

final displacement lf = 0.39 m

5 0

2 years ago

The line of latitude that is zero degrees latitude is the

Nuetrik [128]

Answer:

Equator

Explanation:

The equator is the line of latitude that separates the earth into the northern and southern hemisphere.Its magnitude is 0 degrees latitude. The equator and other lines of latitude are parallel to each other. The lines of longitude which is 0 degrees is known as the Greenwich meridian. The longitudinal lines however are not parallel as they converge at the poles.

7 0

2 years ago

yaroslaw [1]

Answer:

12 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 7.6 kg

Distance (d) = 6 m

Velocity (v) = 5 m/s

Force (F) = 2 N

Workdone (Wd) =.?

Workdone can be defined as the product of force and distance moved in the direction of the force. Mathematically, it is expressed as:

Workdone = Force × distance

Wd = F × d

With the above formula, we can obtain the workdone as follow:

Distance (d) = 6 m

Force (F) = 2 N

Workdone (Wd) =.?

Wd = F × d

Wd = 2 × 6

Wd = 12 J

Thus, the workdone is 12 J

6 0

2 years ago

for an object that is speeding up in the positive direction, what does the displacement vs. time graph look like?

slava [35]

Answer:

The speeding up is steady, it is a parabola (a=V*t+(at^2)/2), and give it's an equation in connection to time, at that point, it is conceivable to discover the separation recipe by utilizing more substantial amount mathematics(integrals).

Explanation:

7 0

3 years ago

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