Answer:
Option A. y = x² + 7x + 10
Step-by-step explanation:
We'll begin calculating the roots of the equation from the graph.
The roots of the equation on the graph is where the curve passes through the x-axis.
The curve passes through the x-axis at –5 and –2
Next, we shall determine the equation. This can be obtained as follow:
x = –5 or x = –2
x + 5 = 0 or x + 2 = 0
(x + 5)(x + 2) = 0
Expand
x(x + 2) + 5(x + 2) = 0
x² + 2x + 5x + 10 = 0
x² + 7x + 10 = 0
y = x² + 7x + 10
Thus, the function that describes the graph is y = x² + 7x + 10
Answer:
25/64
Step-by-step explanation:
C=πd
find diameter:
small= 15 x 15= 225
large= 24 x 24= 576
multiply:
225 x 3.14= 706.5
576 x 3.14= 1808.64
ratio:
706.5/1808.64
reduce:
25/64
Answer: She has 21.63 more euros than pounds and has 1.23 times more euros than pounds.
Step-by-step explanation:
She has US$300, and she will withdraw half of it on pounds, and half of it in euros.
(half of US$300 is US$150)
We know that:
1 pound = US$1.6
(1 pound/US$1.6) = 1
Then US$150 = US$150*(1 pound/US$1.6) = (150/1.6) pounds = 93.75 pounds.
And we also know that:
1 euro = US$ 1.3
then:
(1 euro/US$ 1.3) = 1
This means that:
US$150 = US$150*(1 euro/US$ 1.3) = (150/1.3) euros = 115.38 euros.
This means that:
115.38 - 93.75 = 21.63
This means that she has 21.63 more euros than pounds.
and:
115.38/93.75 = 1.23
She has 1.23 times more euros than pounds.
Answer:
C
Step-by-step explanation:
Because c has the variables in the right spot and the other ones don't make scene
Given the figure of a regular pyramid
The base of the pyramid is a hexagon with a side length = 6
The lateral area is 6 times the area of one of the side triangles
So, the side triangle has a base = 6
The height will be:
![\begin{gathered} h^2=6^2+(\frac{\sqrt[]{3}}{2}\cdot6)^2=36+27=63 \\ h=\sqrt[]{63} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20h%5E2%3D6%5E2%2B%28%5Cfrac%7B%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%5Ccdot6%29%5E2%3D36%2B27%3D63%20%5C%5C%20h%3D%5Csqrt%5B%5D%7B63%7D%20%5Cend%7Bgathered%7D)
so, the lateral area =
![6\cdot\frac{1}{2}\cdot6\cdot\sqrt[]{63}=18\sqrt[]{63}](https://tex.z-dn.net/?f=6%5Ccdot%5Cfrac%7B1%7D%7B2%7D%5Ccdot6%5Ccdot%5Csqrt%5B%5D%7B63%7D%3D18%5Csqrt%5B%5D%7B63%7D)
