Answer:
The equilibrium temperature of the coffee is 72.4 °C
Explanation:
Step 1: Data given
Mass of cream = 15.0 grams
Temperature of the cream = 10.0°C
Mass of the coffee = 150.0 grams
Temperature of the coffee = 78.6 °C
C = respective specific heat of the substances( same as water) = 4.184 J/g°C
Step 2: Calculate the equilibrium temperature
m(cream)*C*(T2-T1) = -m(coffee)*c*(T2-T1)
15.0 g* 4.184 J/g°C *(T2 - 10.0°C) = -150.0g *4.184 J/g°C*(T2-78.6°C)
62.76T2 - 627.6 = -627.6T2 + 49329.36
690.36T2 = 49956.96
T2 = 72.4 °C
The equilibrium temperature of the coffee is 72.4 °C
Answer:
Explanation:
<em>First calculate how many moles of O2 you have. O is 16g/mole, so O2 is 32g/mole. 50/32 = 1.5625 moles. 1 mole of any gas at stp is 22.4 liters.</em>
<em>1.5625 × 22.4 = 35 liters.</em>
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The formula for Cs and S is Cs₂S.
For Cs and S,
Ions formed will be Cs⁺ and S²⁻
As cesium belongs to group 1A and sulfur belongs to group 6A. Therefore, the condensed electronic configuration is -
For Cs is [Xe} 6s¹ and for S is [Ne] 3s²3p⁴.
Cs have 1 valence electron and S have 6 valence electrons.
Hence to attain a stable electronic configuration, both two Cs atoms lose one electron and form Cs⁺ and these two electrons will be accepted by one S atom to form S²⁻.
Therefore the formula for the compound is Cs₂S as Cs donate 1 electron and S will accept 2 electrons from Cs.
The formula is Cs₂S.
To learn more about electronic configuration, visit: brainly.com/question/15051483
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Answer:
A hydrocarbon is any of a class of organic chemicals made up of only the elements carbon (C) and hydrogen (H). The carbon atoms join together to form the framework of the compound, and the hydrogen atoms attach to them in many different configurations
Mass was conserved, because it was losing all shape, weight, and matter. It really has no mass.
