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Lelechka [254]
3 years ago
13

(-2-4)*8 help me solve this

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0
PEMDAS  (the correct order of operations) starts with ' P '. 
That tells you to take care of anything that's inside parentheses
before you move out of the parentheses and do anything else.

(-2-4) is  (-6), and the the whole problem is then simply  -6 * 8 .

I'm pretty sure you can handle it from there.
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Please help me on this it a about to be due
makvit [3.9K]

Answer:

A

Step-by-step explanation:

sin is opposite/hypotenuse, which is 24/26, simplifying to 12/13

8 0
3 years ago
Read 2 more answers
3. Use the diagram 2 and 3 are ____ angles 1. complementary 2. vertical 3. right 4. supplementary
Vladimir79 [104]

#3

2 and three are supplementary angles .

#4.

The answer is opposite angles .

  • Hence there is no option

#5

Bisected angles are equal

\\ \sf\longmapsto 5x=3x+10

\\ \sf\longmapsto 5x-3x=10

\\ \sf\longmapsto 2x=10

\\ \sf\longmapsto x=\dfrac{10}{2}

\\ \sf\longmapsto x=5

Now

m<ABC

\\ \sf\longmapsto 5x+3x+10

\\ \sf\longmapsto 8x+10

\\ \sf\longmapsto 8(5)+10

\\ \sf\longmapsto 40+10

\\ \sf\longmapsto 50

5 0
2 years ago
Read 2 more answers
What is the sequence of transformations that maps △ABC to △A′B′C′ ? Select from the drop-down menus to correctly identify each s
torisob [31]
<h3>Answer:</h3>

Any 1 of the following transformations will work. There are others that are also possible.

  • translation up 4 units, followed by rotation CCW by 90°.
  • rotation CCW by 90°, followed by translation left 4 units.
  • rotation CCW 90° about the center (-2, -2).
<h3>Step-by-step explanation:</h3>

The order of vertices ABC is clockwise, as is the order of vertices A'B'C'. Thus, if reflection is involved, there are two (or some other even number of) reflections.

The orientation of line CA is to the east. The orientation of line C'A' is to the north, so the figure has been rotated 90° CCW. In general, such rotation can be accomplished by a single transformation about a suitably chosen center. Here, we're told there is <em>a sequence of transformations</em> involved, so a single rotation is probably not of interest.

If we rotate the figure 90° CCW, we find it ends up 4 units east of the final position. So, one possible transformation is 90° CCW + translation left 4 units.

If we rotate the final figure 90° CW, we find it ends up 4 units north of the starting position. So, another possible transformation is translation up 4 units + rotation 90° CCW.

Of course, rotation 90° CCW in either case is the same as rotation 270° CW.

_____

We have described transformations that will work. What we don't know is what is in your drop-down menu lists. There are many other transformations that will also work, so guessing the one you have available is difficult.

5 0
3 years ago
The hypotenuese of an isosceles right triangle is 13 inches. The midpoints of its sides are connected to form an inscribed trian
Georgia [21]

Answer:

The Sum of the areas of theses triangles is 169/3.

Step-by-step explanation:

Consider the provided information.

The hypotenuse of an isosceles right triangle is 13 inches.

Therefore,

x^2+x^2=169\\2x^2=169\\x=\frac{13}{\sqrt{2} }

Then the area of isosceles right triangle will be: A=\frac{1}{2} x^2

Therefore the area is: A=\frac{169}{4}

It is given that sum of the area of these triangles if this process is continued infinitely.

We can find the sum of the area using infinite geometric series formula.

S=\frac{a}{1-r}

Substitute a=\frac{169}{4} \ and\ r=\frac{1}{4} in above formula.

S=\frac{\frac{169}{4}}{1-\frac{1}{4}}

S=\frac{\frac{169}{4}}{\frac{3}{4}}

S=\frac{169}{3}

Hence, the Sum of the areas of theses triangles is 169/3.

7 0
3 years ago
F (x) = -x2 + 8x - 11<br> h(x) = -x-7<br> find f (9) + (-14)
bixtya [17]
Is there a answer choice of -5
5 0
2 years ago
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