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Lelechka [254]
3 years ago
13

(-2-4)*8 help me solve this

Mathematics
1 answer:
Hitman42 [59]3 years ago
6 0
PEMDAS  (the correct order of operations) starts with ' P '. 
That tells you to take care of anything that's inside parentheses
before you move out of the parentheses and do anything else.

(-2-4) is  (-6), and the the whole problem is then simply  -6 * 8 .

I'm pretty sure you can handle it from there.
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Help! 10 Points not 5!
KATRIN_1 [288]

9514 1404 393

Answer:

  18

Step-by-step explanation:

Solve the first for a, then substitute into the second.

  a = 27/(5b^2)

Then ...

  (27/(5b^2))^2·b = 135

  27^2/(5^2·135) = b^3 = 27/125

  b = ∛(27/125) = 3/5

  a = 27/(5(3/5)^2) = 15

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The expression of interest is ...

  a +5b = 15 + 5(3/5) = 15 +3

  a +5b = 18

6 0
3 years ago
Which function family would be used to solve the following question?
padilas [110]

Answer:

C

Step-by-step explanation:

.jst c . i thnk it is.............

6 0
2 years ago
Would the hypotenuse of a right triangle with a vertical length of 6 and a horizontal length of 10 have the same slope as the hy
Elodia [21]
No

1. Vertical 6, horizontal 10
6/10 = 3/5 slope

2. (Red) vertical -2, horizontal 3
-2/3 does not equal 3/5

3. (Blue) vertical 4, horizontal 6
4/6 = 2/3 but does not equal 3/5
3 0
2 years ago
Can anybody help me with this? <br> This question is confusing and I don't get it.
Lunna [17]

Answer:

JH = 8, GH = 12, and GJ = 10.6

Step-by-step explanation:

According to Midsegment Theorem, a segment that connects the midpoints of two sides of a triangle is half the length of the third side.

GH = ½ DE

JH = ½ DF

GJ = ½ EF

DE is 24, so GH = 12.

JH is half of DF.  Since G is the midpoint of DF, DG is also half of DF.  So JH = DG = 8.

GJ is half of EF.  Since H is the midpoint of EF, HE is also half of EF.  So GJ = HE = 10.6.

4 0
3 years ago
A rectangle has a length at least four more than five times the width. if the perimeter is at least 44 units. find the least pos
Eva8 [605]
The answer is 3 and you get that by using the formula for the area of rectangle, p=2L+2W
44=2(4+5w) + 2w
44=8+10w + 2w
44=8+12w
44-8=8+12w-8
36=12w
36/12=12w/12
3=w
If you plug 3 back into the original formula then you see that it is equal to the perimeter of 44
P=2(4+5w) + 2w
P=2(4+5•3) + 2(3)
P=2(19) +6
P=38+6
P=44
8 0
3 years ago
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