Ask question

Ask question

All categories

3 years ago

10

an amusement parks goal is to sell 1 million tickets within the first four months of its being open how many more tickets xoes t

he park need to sell in month 4 to reach this goal

1 answer:

Fantom [35]3 years ago

6 0

Answer:

since I don't know how many tickets they already have, I'm going to divide 1 million by 4 and say that they need to sell 250,000 tickets a month

Step-by-step explanation:

You might be interested in

Solve the equation a = m - n for the variable n. *

mart [117]

Answer:

n = m-a

Step-by-step explanation:

a = m-n

a+n =m

n = m-a

3 0

3 years ago

Marta is solving the equation S = 2πrh + 2πr2 for h. Which should be the result?

geniusboy [140]

Step-by-step explanation:

$S = 2\pi rh + 2\pi {r}^{2} h \\ \\ \therefore \: S = (2\pi r + 2\pi {r}^{2}) h \\ \\ \therefore \: S = 2\pi r(1 + {r}) h \\ \\ \huge \purple{ \boxed{\therefore \: h = \frac{S}{2\pi r(1 + {r})} }}\\$

4 0

3 years ago

Read 2 more answers

A car travels 100 miles east in 2 hours and 30 miles north in half an hour. What is the average speed of the car?

Gennadij [26K]

Answer:

44 mph

mph= miles per hour

Step-by-step explanation:

your welcome <3

6 0

3 years ago

C. Neilsen reported that children between the ages of 2 and 5 watch an average of 25 hours of television per week. Assume the va

zubka84 [21]

The following information about the mean and standard deviation has been provided:

ц=25, б=3,n=20

We need to compute Pr(X⁻≥26.3).

The corresponding z-value needed to be computed is:

$Z=\frac{X-u}{o/\sqrt{n} } =\frac{26.3-25}{3/\sqrt{20} }=1.9379$

Therefor, we get that

$Pr(X\geq 26.3)=Pr(Z\geq \frac{26.3-25}{3/\sqrt{20} } )=Pr(Z\geq 1.9379)\\=1-0.9737=0.026$

3 0

3 years ago

A card was selected at random from a standard deck of cards. The suit of the card was recorded, and then the card was put back i

aleksklad [387]

Answer:

30%

Step-by-step explanation:

6 0

3 years ago