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AlekseyPX
3 years ago
12

HURRY

Chemistry
1 answer:
zmey [24]3 years ago
8 0

Answer:

Percent yield of reaction is 75%.

Explanation:

Given data:

Moles of A = 2.0 mol

Moles of B = 4.0 mol

Moles of C formed = 1.8 mol

Percent yield of reaction = ?

Solution:

Chemical equation:

2A + 5B     →      3C +  D

We will compare the moles of A and B with C from balance chemical equation.

                A         :          C

                2         :           3

               B          :         C

                 5         :         3

                 4         :        3/5×4 = 2.4 mol

Number of moles of C formed by 4 moles B are less thus B is limiting reactant and will limit the yield of C.

Percent yield:

Percent yield =  actual yield /theoretical yield × 100

Percent yield = 1.8 mol / 2.4  × 100

Percent yield =75%

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Looking at all the equations, it is only the last equation that has a solid product and so this is the only precipitation reaction. A precipitate for Iron(II)carbonate is formed in it.

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3 years ago
Monosodium glutamate (NaC5H8NO4) is used extensively as a flavor enhancer what is its percent composition
tensa zangetsu [6.8K]

Answer:

% sodium= 13.6 % sodium

% carbon= 35.5 % carbon

% hydrogen= 4.7% hydrogen

% nitrogen = 8.3% nitrogen

% oxygen = 37.8 % oxygen

Explanation:

To find its percent composition means that we are to find to find the percentage of each of the constituents of the compound present.

The molar mass of monosodium glutamate is 169.11 gmol-1

Hence;

Percent of sodium= 23 gmol-1/169.11 gmol-1 × 100 = 13.6 % sodium

Percent of Carbon= 60 gmol-1/169.11 gmol-1 ×100 = 35.5 % carbon

Percent of hydrogen= 8/169.11 gmol-1 ×100 = 4.7% hydrogen

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3 0
3 years ago
1.00 mole of an ideal gas at STP is cooled to -41°C while the
qwelly [4]

Answer:

V₂ = 18.13 L

Explanation:

Given data:

Mole of gas = 1 mol

Initial temperature = 273 K

Initial pressure = 1 atm

Final volume = ?

Final temperature = -41°C (-41+273 = 232 K)

Final pressure = 805 mmHg (805/760 = 1.05 atm)

Solution:

First of all we will calculate the initial volume of gas.

PV = nRT

V = nRT/P

V = 1 mol × 0.0821 mol.L/atm.K × 273 K / 1 atm

V = 22.4 L/atm / 1 atm

V = 22.4 L     ( initial volume)

Now we will determine the final volume by using equation,

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Now we will put the values.

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1 atm × 22.4 L ×  232 K / 273 K × 1.05 atm

V₂ = 5196.8 atm .L. K / 286.65 atm.K

V₂ = 18.13 L

5 0
3 years ago
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