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AlekseyPX
3 years ago
12

HURRY

Chemistry
1 answer:
zmey [24]3 years ago
8 0

Answer:

Percent yield of reaction is 75%.

Explanation:

Given data:

Moles of A = 2.0 mol

Moles of B = 4.0 mol

Moles of C formed = 1.8 mol

Percent yield of reaction = ?

Solution:

Chemical equation:

2A + 5B     →      3C +  D

We will compare the moles of A and B with C from balance chemical equation.

                A         :          C

                2         :           3

               B          :         C

                 5         :         3

                 4         :        3/5×4 = 2.4 mol

Number of moles of C formed by 4 moles B are less thus B is limiting reactant and will limit the yield of C.

Percent yield:

Percent yield =  actual yield /theoretical yield × 100

Percent yield = 1.8 mol / 2.4  × 100

Percent yield =75%

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Ad libitum [116K]

5

 mL acetic acid

95

mL water

Explanation:

Since

5

%

of the vinegar, by volume, is acetic acid, and we have

100

mL of vinegar, we have

5

mL of vinegar.

Similarly, we have

100

%

−

5

%

=

95

%

being water, so we have

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8 0
3 years ago
PLEASE SOMEONE! The density of the acetic acid solution is 1.05 g/mL. Calculate the %(m/m) of the acetic acid solution (convert
tigry1 [53]

Answer:

The Percentage concentration of acetic acid = 1.39 %

Explanation:

Density of acetic acid solution = 1.05 g/mL

Volume of acetic acid solution = 0.1 L = 100 mL

From the formula, Density = mass / volume; mass = density × volume

Mass of acetic acid solution = 1.05 g/mL × 100 mL = 105 g

Molar concentration of acetic acid solution = 0.243 mol/L

Molar mass of acetic acid, CH₃COOH = (12 × 2 + 1 ×4 + 16 ×2) = 60 g/mol

From the formula, mass concentration = molar concentration × molar mass

Mass concentration of acetic acid, CH₃COOH = 0.243 mol/L × 60 g/mol = 14.58 g/L

In one liter of acetic acid solution, there are 14.58 g of acetic acid. Therefore, in 0.1 L, there will be 14.58 × 0.1 = 1.458 g of acetic acid.

Percentage concentration of acetic acid = mass of acetic acid / mass of acetic acid solution × 100%

Percentage concentration of acetic acid = (1.458 / 105) × 100% = 1.39 %

The Percentage concentration of acetic acid = 1.39 %

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6 0
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