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2 years ago

HURRY

Chemistry

1 answer:

zmey [24]2 years ago

8 0

Answer:

Percent yield of reaction is 75%.

Explanation:

Given data:

Moles of A = 2.0 mol

Moles of B = 4.0 mol

Moles of C formed = 1.8 mol

Percent yield of reaction = ?

Solution:

Chemical equation:

2A + 5B → 3C + D

We will compare the moles of A and B with C from balance chemical equation.

A : C

2 : 3

B : C

5 : 3

4 : 3/5×4 = 2.4 mol

Number of moles of C formed by 4 moles B are less thus B is limiting reactant and will limit the yield of C.

Percent yield:

Percent yield = actual yield /theoretical yield × 100

Percent yield = 1.8 mol / 2.4 × 100

Percent yield =75%

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Vlad [161]

Answer:

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Explanation:

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2 years ago

If a reaction mixture contains 24 g of Mg and 32 g of O2 , what is the limiting reactant?

Alexxx [7]

This problem is providing the mass of both magnesium metal and oxygen gas and involved in a chemical reaction and asks for the limiting reactant. At the end, it turns out to be identified as magnesium.

<h3>Stoichiometry</h3>

In chemistry, stoichiometry is a widely-used tool we use in order to relate the mass and moles of different chemical substances involved in a chemical reaction. Thus, we consider the following chemical equation between magnesium and oxygen to produce magnesium oxide.

$2Mg+O_2\rightarrow 2MgO$

However, when the mass of the both of the reactants is given, one must identify the limiting reactant as the one producing the least of the moles of the product, which means we can use the given grams of the both of the reactants, their molar masses and mole ratios with the product to obtain the aforementioned:

$24gMg*\frac{1molMg}{24.3gMg}*\frac{2molMgO}{2molMg}=0.988molMgO\\ \\ 32gO_2*\frac{1molO_2}{32.0gO_2}*\frac{2molMgO}{1molO_2}=2molMgO$

Thus, we can evidence how 24 g of magnesium produce the least of the moles of magnesium oxide, fact validating the magnesium as the limiting reactant and the oxygen as the excess one.

Learn more about stoichiometry: brainly.com/question/9743981

3 0

2 years ago

¿Como pasar 254 meses a minutos?<br> Por favor ayudaaa!! <br> Le doy corona a la respuesta

Dimas [21]

Answer:

Ver las respuestas abajo.

Explanation:

Este problema se puede resolver conociendo la relacion entre horas y minutos, sabemos que:

1 hora [h] → 60 minutos [min]

De esta manera:

2 [min] = 2/60 = 0.033 [h]

15 [min] = 15/60 = 0.25 [h]

30 [min] = 30/60 = 0.5 [h]

10 [min] = 10/60 = 0.166 [h]

6 [min] = 6/60 = 0.1 [h]

20 [min] = 20/60 = 0.33 [h]

5 [min] = 5/60 = 0.0833 [h]

7 0

3 years ago

What eventually happens to gas if its pressureis increased?

balu736 [363]

Answer:

the rate increases

Explanation:

they are closer to each other, they will collide with each other more frequently and more successful collision

4 0

2 years ago

The molar solubility of pbi2 is 1.5 103 m.

Vsevolod [243]

Answer: -

Concentration of PbI₂ = 1.5 x 10⁻³ M

PbI₂ dissociates in water as

PbI₂ ⇄ Pb²⁺ + 2 I⁻

So PbI₂ releases two times the amount of I⁻ as it's own concentration when saturated.

Thus the molar concentration of iodide ion in a saturated PbI₂ solution = [ I⁻] =

= 1.5 x 10⁻³ x 2 M

= 3 x 10⁻³ M

PbI₂ releases the same amount of Pb²⁺ as it's own concentration when saturated.

[Pb²⁺] = 1.5 x 10⁻³ M

So solubility product for PbI₂

Ksp = [Pb²⁺] x [ I⁻]²

=1.5 x 10⁻³ x (3 x 10⁻³)²

= 4.5 x 10⁻⁹

8 0

2 years ago