Answer:
12 oxygen atoms are in 4 molecules of HNO3?
Explanation:
the amounts of atoms of all the component in HNO3, which are 1 atom of Hydrogen, 1 atom of Nitrogen and 3 atoms of Oxygen.
Answer:27,430J/g.K
Explanation:q= mass* specific heat capacity * change in temperature (kelvin)
22*4.184*[(100-25) + 273]
22*4.184*298
27,430J/g.K
fluorine, F2, chlorine, Cl2, bromine, Br2, or iodine, I2
Answer:
Volume = 44.96L
Explanation:
p = 427mmHg = 0.56atm
R = 0.08206
T 6°C = 279k
V = ?
n = 1.10 mol
using ideal gas equation
pv=nRT
0.56 x V = 1.10 x 0.08206 x 279
0.56 x V = 25.18
V = 25.18/0.56
V = 44.96L
<span>[Ar]4s²3d¹⁰4p⁴
We see that the last level is this element is 4, so this element should be in
4th period, it has 4 p-electrons, so it should be in 16th group.
4th period, 16th group - it is Se.
You can also go to the next element after Ar, and count beginning of this element 16. (2+10+4 =16 electrons)
From "K" (where K is the first) you count to 16 and it is going to be Se.</span>
