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3 years ago

During the war where did African-Americans receive the best treatment?

Chemistry

1 answer:

Sindrei [870]3 years ago

7 0

Hope this helps. Sorry of it is long

Answer: military

African Americans received the best treatment in the military during war. Making up about 3/4 of the military, African American soldiers proved their efficiency and ability to serve the country, thus receiving more respect from society than if they were to work in more "common" jobs, for example in a factory. However, while they received the best treatment in the military during the war, African Americans still faced segregation within the units of the military, an important fact to note.

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A vessel of volume 22.4 dm3 contains 2.0 mol h2 and 1.0 mol n2 at 273.15 k initially. all the h2 reacted with sufficient n2 to f

yanalaym [24]

Volume = 22.4 dm3
n = 2 mol of H2
n = 1 mol of N2
Temperature = 273.15
All H2 reacts
reaction
N2 + 3H2 = 2NH3
1:3 ratio
Calculation:
N2 initial - N2 reacted = Final N2
1 - 2*(1/3) = 0.3333 mol of N2 left
H2 = 0 left
NH3 formed = 2/3*1 = 2/3 = 0.666
Total mol:
0.3333 + 0.666 = 1 mol
Apply the equation :
PV = nRT
P = nRT/V = 1*0.0082*(273.15)/(22.4) = 0.0999924 atm
PH2 = 0
PN2 = 1/3*0.0999924 = 0.0333308 atm
PNH3 = 2/3*0.0999924 = 0.0666616 atm
Answer is 0.0666616 atm

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3 years ago

Which of the following is true about gravity? <br><br> Select all that apply.

Ivenika [448]

Answer:

its always attractive

Explanation:

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2 years ago

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What can longitudinal waves travle though?

Sever21 [200]

They travel through all medium types

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3 years ago

The allotropic form of a non – metal is a good conductor of electricity. Name the nonmetal.

SashulF [63]

Answer:

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2 years ago

When the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is

gizmo_the_mogwai [7]

Answer : The correct option is, (D) 100 times the original content.

Explanation :

As we are given the pH of the solution change. Now we have to calculate the ratio of the hydronium ion concentration at pH = 5 and pH = 3

As we know that,

$pH=-\log [H_3O^+]$

The hydronium ion concentration at pH = 5.

$5=-\log [H_3O^+]$

$[H_3O^+]=1\times 10^{-5}M$ ..............(1)

The hydronium ion concentration at pH = 3.

$3=-\log [H_3O^+]$

$[H_3O^+]=1\times 10^{-3}M$ ................(2)

By dividing the equation 1 and 2 we get the ratio of the hydronium ion concentration.

$\frac{[H_3O^+]_{original}}{[H_3O^+]_{final}}=\frac{1\times 10^{-5}}{1\times 10^{-3}}=\frac{1}{100}$

$100\times [H_3O^+]_{original}=[H_3O^+]_{final}$

From this we conclude that when the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is 100 times the original content.

Hence, the correct option is, (D) 100 times the original content.

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3 years ago

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