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Anna71 [15]
2 years ago
6

If –y + 2x^2 – x = -5y^3 then find dy / dx in terms of x and y.

Mathematics
1 answer:
vlada-n [284]2 years ago
8 0

Answer:

dy/dx = \frac{4x-1}{1-15y^{2} }

Step-by-step explanation:

-y + 2x²- x = -5y³

2x² - x = y - 5y³

4x - 1 = dy/dx - 15y².dy/dx

dy/dx(1 - 15y²) = 4x - 1

dy/dx = \frac{4x-1}{1-15y^{2} }

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Given that cos(theta) = 8/17 and that theta lies in Quadrant IV, what is the exact value of sin 2(theta)?
Deffense [45]

Answer:    -\frac{240}{289}

=========================================================

Explanation:

Use the pythagorean trig identity \sin^2(\theta)+\cos^2(\theta) = 1 and plug in the fact that \cos(\theta) = \frac{8}{17}\\\\

Isolating sine leads to \sin(\theta) = -\frac{15}{17}\\\\. I'm skipping the steps here, but let me know if you need to see them.

The result is negative because we're in quadrant 4, when y < 0 so it's when sine is negative.

Therefore,

\sin(2\theta) = 2\sin(\theta)\cos(\theta)\\\\\sin(2\theta) = 2*\left(-\frac{15}{17}\right)*\left(\frac{8}{17}\right)\\\\\sin(2\theta) = -\frac{240}{289}\\\\

6 0
1 year ago
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maks197457 [2]

Answer:

Step-by-step explanation:

use desmos.com

6 0
2 years ago
If f(x) = 2x + 3 and g(x) = 3x - 9, find (f + g)(x).
coldgirl [10]

Answer:

5x-6

Step-by-step explanation:

f(x) = 2x + 3

g(x) = 3x - 9

f(x) + g(x) = 2x + 3  + 3x-9

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5 0
3 years ago
Please help its urgent ​
hram777 [196]

Answer:

<h2>Function is y = x.</h2><h2>Domain: -3 \leq x \leq 2.</h2><h2>Range: -5 \leq y \leq 4.</h2>

Step-by-step explanation:

In the given image, the line passes through (-1, -1) and (1, 1).

Let the equation of the line is y = mx + c, where m is the tangent of the line and c is a constant.

Putting the co-ordinates of the points in the equation, we get -1 = -m + c and 1 = m + c

From the two equations we get, c = 0 and m = 1.

Hence, the function is y = x.

Domain is -3 \leq x \leq 2.

Range is -5 \leq y \leq 4

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3 years ago
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grin007 [14]

Answer:

0.75

Step-by-step explanation:

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2 years ago
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