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2 years ago

If –y + 2x^2 – x = -5y^3 then find dy / dx in terms of x and y.

Mathematics

1 answer:

vlada-n [284]2 years ago

8 0

Answer:

dy/dx = $\frac{4x-1}{1-15y^{2} }$

Step-by-step explanation:

-y + 2x²- x = -5y³

2x² - x = y - 5y³

4x - 1 = dy/dx - 15y².dy/dx

dy/dx(1 - 15y²) = 4x - 1

dy/dx = $\frac{4x-1}{1-15y^{2} }$

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The shaded region in the graph represents the solutions of this system of linear inequalities:

kotegsom [21]

Answer:

$y$

$y\leq 2x+3$

Step-by-step explanation:

step 1

Find the equation of the solid line

From the graph take the points (0,3) and (4,11)

Find the slope

$m=(11-3)/(4-0)\\m=8/4=2$

The equation of the solid line in slope intercept form is equal to

$y=mx+b$

we have

$m=2$

$b=3$ ----> the y-intercept is the point (0,3)

substitute

$y=2x+3$

therefore

The inequality is

$y\leq 2x+3$

step 2

Find the equation of the dashed line

The slope is given

$m=4$

From the graph take the y-intercept (0,-5)

The equation of the solid line in slope intercept form is equal to

$y=mx+b$

we have

$m=4$

$b=-5$

substitute

$y=4x-5$

therefore

The inequality is

$y$

because the shaded region is below the dashed line

therefore

The system of inequalities is

$y$

$y\leq 2x+3$

8 0

2 years ago

A quantity b varies jointly with c and d and inversely with eWhen b is 18, c is 4, d is 9, and e is 6What is the constant of var

777dan777 [17]

Answer:

constant of variation = 3

Step-by-step explanation:

we know that b varies jointly with c and d

so:

b∝c∝d

and b varies inversely with e, so

b∝ $\frac{1}{e}$

and i will call the constant of variation k, this way we can make an equation for b in the following form:

$b=k\frac{cd}{e}$

this satisfy that b varies jointly with c and d (if b increases, c and d also increase) and inversely with e (if b increases, e decreases)

we know that when b is 18, c is 4, d is 9, and e is 6:

$b=18\\c=4\\d=9\\e=6$

substituting this in our equation for b:

$b=k\frac{cd}{e}\\ 18=k\frac{(4)(9)}{6}$

and we solve operations and clear for the constant of variation k:

$18=k\frac{36}{6}\\ 18=6k\\\frac{18}{6}=k\\ 3=k$

the constant of variation is 3.

4 0

2 years ago

Read 2 more answers

Find the component form of the vector that translates P(4,5) to p'.

Veronika [31]

Answer:

Component form : (-7 , 2)

Step-by-step explanation:

P(4 , 5) = P'(4 +x , 5+y) = P'(-3 , 7)

4 + x = -3

x = -3 - 4

x = -7

5 + y = 7

y = 7 - 5

y = 2

Vector form : -7i + 2j

Component form : (-7 , 2)

4 0

2 years ago

How many terms are in the binomial expansion of (3x 5)9? 8 9 10 11

swat32

Answer:

Step-by-step explanation:

5 0

1 year ago

Find the particular solution that satisfies the differential equation and the initial condition.

Vesnalui [34]

Answer:

1) $y =4x^2 +7$

2) $y =7s^2 -3s^4 +181$

Step-by-step explanation:

Assuming that our function is $y = f(x)$ for the first case and $y=f(s)$ for the second case.

Part 1

We can rewrite the expression like this:

$\frac{dy}{dx} =8x$

And we can reorder the terms like this:

$dy = 8 x dx$

Now if we apply integral in both sides we got:

$\int dy = 8 \int x dx$

And after do the integrals we got:

$y = 4x^2 +c$

Now we can use the initial condition $y(0) =7$

$7 = 4(0)^2 +c, c=7$

And the final solution would be:

$y =4x^2 +7$

Part 2

We can rewrite the expression like this:

$\frac{dy}{ds} =14s -12s^3$

And we can reorder the terms like this:

$dy = 14s -12s^3 dx$

Now if we apply integral in both sides we got:

$\int dy = \int 14s -12s^3 ds$

And after do the integrals we got:

$y = 7s^2 -3s^4 +c$

Now we can use the initial condition $y(3) =1$

$1 = 7(3)^2 -3(3)^4 +c, c=1-63+243=181$

And the final solution would be:

$y =7s^2 -3s^4 +181$

7 0

3 years ago