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posledela
3 years ago
6

brad studied a total of 24.4 hours over a period of four days. On average, how many hours did brad study each day?

Mathematics
2 answers:
stiv31 [10]3 years ago
8 0
He studied about 6 hours each day. Just divide 24.4 by 6 . If you want to give an accurate answer then it would be 6.1
Nady [450]3 years ago
6 0
24.4/4 =6.1 hours daily is the average hour per day
You might be interested in
Matthew drove 74 miles in 2 hours. On average, how fast did he drive in hours per mile? Express your answer in simplest form.
jonny [76]

Answer: 37

Step-by-step explanation: Since you drove 74 miles in 2 hours, you would divide 74 by 2 to find the miles per hour, which would be 37.

3 0
3 years ago
A sample of 100 workers located in Atlanta has an average daily work time of 6.5 hours with a standard deviation of 0.5 hours. A
Readme [11.4K]

Answer:

t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398  

df = n_1 +n_2 -2= 100+110-2= 208

Since is a bilateral test the p value would be:

p_v =2*P(t_{208}

Comparing the p value with the significance level given \alpha=0.05 we see that p_v so we can conclude that we can reject the null hypothesis, and we have significant differences between the two groups at 5% of significance.

Step-by-step explanation:

Data given and notation

\bar X_{1}=6.5 represent the sample mean for Atlanta

\bar X_{2}=6.7 represent the sample mean for Chicago

s_{1}=0.5 represent the sample deviation for Atlanta

s_{2}=0.7 represent the sample standard deviation for Chicago

n_{1}=100 sample size for the group Atlanta

n_{2}=110 sample size for the group Chicago

t would represent the statistic (variable of interest)

\alpha=0.01 significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the meanfor atlanta is different from the mean of Chicago, the system of hypothesis would be:

Null hypothesis:\mu_{1}=\mu_{2}

Alternative hypothesis:\mu_{1} \neq \mu_{2}

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

t=\frac{6.5-6.7}{\sqrt{\frac{0.5^2}{100}+\frac{0.7^2}{110}}}}=-2.398  

What is the p-value for this hypothesis test?

The degrees of freedom are given by:

df = n_1 +n_2 -2= 100+110-2= 208

Since is a bilateral test the p value would be:

p_v =2*P(t_{208}

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.05 we see that p_v so we can conclude that we can reject the null hypothesis, and we have significant differences between the two groups at 5% of significance.

3 0
3 years ago
Read 2 more answers
1
skelet666 [1.2K]

Step-by-step explanation:

f°g=f(g(x))

g(x)=x^2-6x

f(x)=1/x

f(g(x))=\frac{1}{x^2-6x}

if the denominator is zero the number is undefined which makes it not in the domain of the function

set x^2-6x equal to 0

the values for x is 0 or 6

so the only value that is not in the domain of f°g is 0 and 6

Hope that helps :)

6 0
2 years ago
I really need help with this please helpp!!!
jolli1 [7]
What do you need help in??
6 0
2 years ago
CDs costs $4 each and DVD cost $8 each.
Licemer1 [7]

Answer:

0 and 4

1 and 3

2 and 2

3 and 1

4 and 0

Step-by-step explanation:

If you need 4 gifts and you want to spend less than $40, then you could buy

1 cd+ 3 dvds for $25

2 cds + 2 dvds for $24

3 cds + 1 dvd for $20

4 cds and 0 dvds for $16

0 cds and 4dvds for $32

Any of these solutions will work

8 0
3 years ago
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