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3 years ago

Which statement best describes the forces in this picture

Physics

2 answers:

garik1379 [7]3 years ago

6 0

Answer:

Explanation:

Force is strength and energy as an attribute of physical action or movement.

Troyanec [42]3 years ago

4 0

Answer:

Explanation:

apex

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The world energy consumption was about 6*10^22 J. How much area must a parallel plate capacitor need to store this energy Assume

Nastasia [14]

Answer:

$A = 5 \times 10^{32} m^2$

Explanation:

As we know that the energy stored in the capacitor is given as

$Q = \frac{1}{2}CV^2$

here we know that

$Q = 6 \times 10^{22} J$

also we know that

$V = 5 Volts$

now we have

$6 \times 10^{22} = \frac{1}{2}C(5^2)$

$C = 4.8 \times 10^{21} F$

now we know the formula of capacitance

$C = \frac{\epsilon_0 A}{d}$

$4.8 \times 10^{21} = \frac{(8.85 \times 10^{-12})(A)}{1}$

$A = 5 \times 10^{32} m^2$

3 0

3 years ago

How can you safely experiment with plants during a scientific investigation?

liubo4ka [24]

I would think the answer is c.

3 0

3 years ago

Read 2 more answers

In order to sail through the frozen Arctic Ocean, the most powerful icebreaker ever built was constructed in the former Soviet U

professor190 [17]

Answer:

955.36 seconds ≈ 16 minutes

Explanation:

Power(P) is the rate of doing work(W)

That is, P = W/t, where t is the time.

multipying both sides with 't' and dividing with 'P', we get: t=W/P

Here, W = 5.35 x 10^10 J and P = 5.6 x 10^7 W ( 1 W = 1 J/s).

Therefore , on dividing W with P, we get 955.36 seconds.

6 0

2 years ago

Find the shear stress and the thickness of the boundary layer (a) at the center and (b) at the trailing edge of a smooth flat pl

melomori [17]

Answer:

a) The shear stress is 0.012

b) The shear stress is 0.0082

c) The total friction drag is 0.329 lbf

Explanation:

Given by the problem:

Length y plate = 2 ft

Width y plate = 10 ft

p = density = 1.938 slug/ft³

v = kinematic viscosity = 1.217x10⁻⁵ft²/s

Absolute viscosity = 2.359x10⁻⁵lbfs/ft²

a) The Reynold number is equal to:

$Re=\frac{1*3}{1.217x10^{-5} } =246507, laminar$

The boundary layer thickness is equal to:

$\delta=\frac{4.91*1}{Re^{0.5} } =\frac{4.91*1}{246507^{0.5} } =0.0098$ ft

The shear stress is equal to:

$\tau=0.332(\frac{2.359x10^{-5}*3 }{1} )(246507)^{0.5} =0.012$

b) If the railing edge is 2 ft, the Reynold number is:

$Re=\frac{2*3}{1.215x10^{-5} } =493015.6,laminar$

The boundary layer is equal to:

$\delta=\frac{4.91*2}{493015.6^{0.5} } =0.000019ft$

The sear stress is equal to:

$\tau=0.332(\frac{2.359x10^{-5}*3 }{2} )(493015.6^{0.5} )=0.0082$

c) The drag coefficient is equal to:

$C=\frac{1.328}{\sqrt{Re} } =\frac{1.328}{\sqrt{493015.6} } ==0.0019$

The friction drag is equal to:

$F=Cp\frac{v^{2} }{2} wL=0.0019*1.938*(\frac{3^{2} }{2} )(10*2)=0.329lbf$

7 0

2 years ago

What is the new volume of the gas if the pressure on 350 L of oxygen

Iteru [2.4K]

Answer:

420 L

Explanation:

Applying Boyle's Law,

PV = P'V'.................... Equation 1

Where P = Initial pressure, P' = Final pressure, V = Initial volume, V' = Final volume.

make V' the subject of the equation

V' = PV/P'.................... Equation 2

From the question,

Given: P = 720 mmHg, V = 350 L, P' = 600 mmHg

Substitute these values into equation 2

V' = (720×350)/600

V' = 252000/600

V' = 420 L

7 0

3 years ago