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inessss [21]
3 years ago
11

Substances whose atoms readily give up electrons are considered to be which of the following?

Physics
1 answer:
nexus9112 [7]3 years ago
6 0
Answer: D
A substance with freely moving electrons is a good conductor of electricity. Metals are an example of good conductors of electricity because of this one property. They have freely moving electrons due to the metallic bonding and they readily give up electrons.
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What happens to the rock structure during each of type of change?
EastWind [94]
Previous rocks melt and collide and to form igneous rocks.
Igneous rocks disintegrate due to weather disruptions and get carried away by water, where they form sedimentary rock strata by lithification.
Igneous and sedimentary change by heat and pressure to form metamorphic rocks.
Metamorphic rocks melt and become igneous rocks.
3 0
3 years ago
As a pendulum swings from its highest to lowest position, what happens to its kinetic and potential energy?
DIA [1.3K]

The potential energy decreases while the kinetic energy increases.



7 0
3 years ago
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Which tagline from a car advertisement has the BEST connotative appeal to the parents of a new teenage driver?
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A.  Advanced new safety features that get everyone home at night.  
6 0
3 years ago
What type of energy can take up space
Arada [10]

Answer:

Yes energy does take up space.

Explanation:

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8 0
3 years ago
Determine the velocity that a car should have while traveling around a frictionless curve of radius 100m and that is banked 20 d
alex41 [277]

Answer:

v=18.89\frac{m}{s}

Explanation:

From the free-body diagram for the car, we have that the normal force has a vertical component and a horizontal component, and this component act as the centripetal force on the car:

\sum F_x:Nsin(20^\circ)=ma_c(1)\\\sum F_y:Ncos(20^\circ)=mg(2)

Solving N from (2) and replacing in (1):

N=\frac{mg}{cos(20^\circ)}\\(\frac{mg}{cos(20^\circ)})sin(20^\circ)=ma_c\\gtan(20^\circ)=a_c

The centripetal acceleration is given by:

a_c=\frac{v^2}{r}

Replacing and solving for v:

gtan(20^\circ)=\frac{v^2}{r}\\v=\sqrt{grtan(20^\circ)}\\v=\sqrt{9.8\frac{m}{s^2}(100m)tan(20^\circ)}\\v=18.89\frac{m}{s}

4 0
3 years ago
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