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3 years ago

Substances whose atoms readily give up electrons are considered to be which of the following?

1 answer:

6 0

Answer: D
A substance with freely moving electrons is a good conductor of electricity. Metals are an example of good conductors of electricity because of this one property. They have freely moving electrons due to the metallic bonding and they readily give up electrons.

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A ball is thrown with an initial speed vi at an angle i with the horizontal. The horizontal range of the ball is R, and the ball

adell [148]

Answer:

Part a)

$T = 2\sqrt{\frac{R}{3g}}$

Part b)

$v_x = \frac{\sqrt{3Rg}}{2}$

Part c)

$v_y = \sqrt{Rg/3}$

Part d)

$v = \frac{1}{2}\sqrt{13Rg}$

Part e)

$\theta_i = 33.7 degree$

Part f)

$H = \frac{13R}{8}$

Part g)

$X = \frac{13R}{4}$

Explanation:

Initial speed of the launch is given as

initial speed = $v_i$

angle = $\theta_i$ degree

Now the two components of the velocity

$v_x = v_i cos\theta_i$

similarly we have

$v_y = v_i sin\theta_i$

Part a)

Now we know that horizontal range is given as

$R = \frac{v_i^2 (2sin\theta_icos\theta_i)}{g}$

maximum height is given as

$H = \frac{R}{6} = \frac{v_i^2 sin^2\theta_i}{2g}$

so we have

$v_i sin\theta = \sqrt{Rg/3}$

time of flight is given as

$T = \frac{2v_isin\theta_i}{g}$

$T = \frac{2\sqrt{Rg/3}}{g}$

$T = 2\sqrt{\frac{R}{3g}}$

Part b)

Now the speed of the ball in x direction is always constant

so at the peak of its path the speed of the ball is given as

$R = v_x T$

$R = v_x 2\sqrt{\frac{R}{3g}}$

$v_x = \frac{\sqrt{3Rg}}{2}$

Part c)

Initial vertical velocity is given as

$v_y = v_i sin\theta_i$

$v_i sin\theta = \sqrt{Rg/3}$

Part d)

Initial speed is given as

$v = \sqrt{v_x^2 + v_y^2}$

so we will have

$v = \sqrt{Rg/3 + 3Rg/4}$

$v = \frac{1}{2}\sqrt{13Rg}$

Part e)

Angle of projection is given as

$tan\theta_i = \frac{v_y}{v_x}$

$tan\theta_i = \frac{\sqrt{Rg/3}}{\sqrt{3Rg}/2}$

$\theta_i = 33.7 degree$

Part f)

If we throw at same speed so that it reach maximum height

then the height will be given as

$H = \frac{v^2}{2g}$

$H = \frac{13R}{8}$

Part g)

For maximum range the angle should be 45 degree

so maximum range is

$X = \frac{v^2}{g}$

$X = \frac{13R}{4}$

3 0

3 years ago

I was processing over this one i can tell u! C or D got me stumped, please help me

r-ruslan [8.4K]

D. be transported from place to place
because it does allow c to happen but not directly as it would have to go through condensation first.
When the water is evaporated in the air it can be moved from place to place by the wind.

3 0

3 years ago

A 12 volt car battery is connected to a 3 ohm brake light. What is the current carrying energy to the lights?

zloy xaker [14]

Answer:

4 A

Explanation:

V = IR, where V=voltage, I=current, R=resistance. This is Ohm's Law. (remember that for units V = volts, Ω = ohms, A = amperes.)

V = IR

12 V = I * 3 Ω

12/3 = I

8 0

3 years ago

When a wire moves through a magnetic field, an electric current is produced in the wire. Why does this phenomenon occur?

Alenkasestr [34]

Answer:

<h2>It occurs whenever a magnetic field and an electric conductor move relative to one another so the conductor crosses lines of force in the magnetic field. </h2>

Explanation:

<h3>The current produced by electromagnetic induction is greater when the magnet or coil moves faster, the coil has more turns, or the magnet is stronger.</h3>

<h2>Carryonlearning </h2>

4 0

2 years ago

Two asteroids in outer space collide, and stick together. The mass of each asteroid, and the velocity of each asteroid before th

Naddik [55]

Answer: (2) Use the Momentum Principle.

Explanation:

In fact, it is called the <u>Conservation of linear momentum principle,</u> which establishes the initial momentum $p_{i}$ of the asteroids before the collision must be equal to the final momentum $p_{f}$ after the collision, no matter if the collision was elastic or inelastic (in which the kinetic energy is not conserved).

In this sense, the linear momentum $p$ of a body is defined as:

$p=mV$

Where $m$ is the mass and $V$ the velocity.

Therefore, the useful approach in this situation is<u> option (2)</u>.

7 0

3 years ago