Answer:
Chemical, mechanical, thermal i guess
The y-component of the acceleration is 
Explanation:
The y-component of the acceleration is given by:

where
is the y-component of the final velocity
is the y-component of the initial velocity
t is the time elapsed
For the ice skater in this problem, we have:

where
u = 2.25 m/s is the initial velocity
is the initial direction
, where
v = 4.65 m/s is the final velocity
is the final direction
The time elapsed is
t = 8.33 s
Therefore, we can find the y-component of the acceleration:

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Answer
Radius of the wheel r = 2.1 m
Moment of inertia I = 2500 Kg m²
Tangential force applied F = 18 N
Time interval t = 16 s
Initial angular speed ω1 = 0
Final angular speed ω2 = ?
Let α be the angular acceleration.
Torque applied τ = Iα
F r = Iα
Angular acceleration α = F r/I
= 
= 0.015 rad/s²
(a)From rotational kinematic relation
Final angular speed ω₂ = ω₁ + αt
= 0 + (0.015 rad/s^2 * 16 s)
= 0.24 rad/s
(b) Work done W = 0.5 Iω₂² - (1/2)Iω₁²
= 0.5*( 2500 Kg m²)(0.24 rad/s)^2 - 0
= 72 J
(c) Average power supplied by the child P = W/t = 
= 4.5 watt
Answer:
By induction method
Explanation:
Induction method involves charging an electrically neutral body by bringing it in contact with an electrically charged body.
For the electrophus, a charge opposite that on the slab is induced on the side in contact with the slab; driving the opposite charge (this will be the same as that on the slab) to the other end of the elctrophus. Touching the electrophus removes the charge opposite the charge induced on the electrophus by the charged slab either by drawing up charge from the earth or taking the charge to earth (depends on the charge. A negative charge is drawn to earth while a positive charge draws up electrons from the earth)
I think the amplitude changed