What is your question exactly? I'm confused?
Answer:
ΔF=125.22 %
Explanation:
We know that drag force on the car given as
=Drag coefficient
A=Projected area
v=Velocity
ρ=Density
All other quantity are constant so we can say that drag force and velocity can be given as
Now by putting the values
Percentage Change in the drag force
ΔF=125.22 %
Therefore force will increase by 125.22 %.
There is no SI "base unit" of density.
(Any unit of mass) divided by (any unit of volume) is
a valid unit of density.
The units of density that are seen most often are
(gram per cm³) and (kgm per meter³) .
Answer: over burden is dissolved by water wind and acids
Answer:
The car exerts a force on the truck which is c.) 6000 N.
Explanation:
If the truck exerts a force of 6000 N on the car then according to Newton's Third Law of Motion that every action has an equal and opposite reaction we can say that the force exerted by the car on the truck is 6000 N.
The only reason the truck is able to move the car is because of the frictional forces. That is frictional force of the trucks tires on the surface of the road and the frictional forces of the cars tire on the surface of the road, and since these forces are not equal this therefore gives rise to motion.