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sladkih [1.3K]
3 years ago
15

Certain mushrooms launch their spores by a catapult mechanism. As water condenses from the air onto a spore that is attached to

the mushroom, a drop grows on one side of the spore and a film grows on the other side. The spore is bent over by the drop's weight, but when the film reaches the drop, the drop's water suddenly spreads into the film and the spore springs upward so rapidly that it is slung off into the air. Typically, the spore reaches a speed of 1.60 m/s in a 5.30 μm launch; its speed is then reduced to zero in 1.30 mm by the air. Using that data and assuming constant accelerations, find the acceleration in terms of g during
(a) the launch and
(b) the speed reduction.
Physics
1 answer:
aleksklad [387]3 years ago
4 0

Answer:

Part a)

a = 2.46 \times 10^4 g

Part b)

a = 100.37 g

Explanation:

Part a)

During the launch

speed will increase from rest to final speed of 1.60 m/s

the distance moved by it is given as

d = 5.30 \mu m

now we have

v_f^2 - v_i^2 = 2ad

1.60^2 - 0 = 2(a)(5.30 \times 10^{-6})

so we have

a = \frac{1.60^2}{2(5.30 \times 10^{-6})}

a = 2.4151 \times 10^5 m/s^2

now in terms of g it is given as

a = 2.46 \times 10^4 g

Part b)

During  speed reduction

we know that final speed will be zero by air in distance 1.30 mm

so we have

v_f^2 - v_i^2 = 2 a d

0 - 1.60^2 = 2(a)(1.30 \times 10^{-3})/tex][tex]a = 984.6 m/s^2

Now in terms of g it is

a = 100.37 g

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A proton with a speed of 3.2 x 106 m/s is shot into a region between two plates that are separated by a distance of 0.23 m. As t
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Answer:

<h2>The magnitude of the magnetic is 0.145 T</h2>

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By comparing above two equation,

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football player A has a mass of 110 kg is running on the field is velocity of 2 m/s football player B has a mass of 120 kg and a
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Complete Question:

Football player A has a mass of 110 kg, and he is running down the field with a velocity of 2 m/s. Football player B has a mass of 120 kg and is stationary. What is the total momentum after the collision?

Answer:

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Explanation:

<u>Given the following data;</u>

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For footballer B

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Velocity, V1 = 0m/s since he's stationary.

To find the total momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

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b. To find the momentum of B;

Momentum \; B = 120 * 0

Momentum B = 0 Kgm/s.

c. To find the total momentum of the two persons;

Total \; momentum = Momentum \; A + Momentum \; B

Substituting into the equation, we have;

Total \; momentum = 220 + 0

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