Step-by-step explanation:
This is the answer. Hope it helps.
Explanation:
Vertex form of a quadratic function is given by y = a(x - h)² + k
where
1) 'a' determines if parabola is stretched or compressed.
If a > 1 then graph is stretched by a factor of a.
If 0 < a < 1, then graph is compressed by a factor of a.
2) If a > 0 then graph opens upwards with a happy face. (minimum)
3) If a < 0 then graph opens downwards with a sad face. (maximum)
4) (h, k) is the vertex point
5) The axis of symmetry is x = h
While solving for y = 1(x - 4)² + 3
Identify following's:
Vertex: (h, k) = (4, 3)
Axis of symmetry: x = 4
Max/Min: As here a > 0, Minimum (4, 3)
Stretch/compression: a = 1, the graph is stretched by a factor of 1.
Direction of opening: As a > 0, the graph opens upwards.
The eccentricity of the conic section that is graphed is C. One.
<h3>What is eccentricity?</h3>
It should be noted that the eccentricity of the clinic section simply means the distance from the point to its focus.
In this case, the eccentricity of the conic section that is graphed is one. The eccentricity value is usually constant for any conics.
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-7x - 2y = -13
-7x + 7x - 2y = 7x - 13
-2y = 7x - 13
-2 -2
y = -3.5x + 6.5
x - 2y = 11
x - 2(-3.5x + 6.5) = 11
x - 2(-3.5x) - 2(6.5) = 11
x + 7x - 13 = 11
8x - 13 = 11
+ 13 + 13
8x = 24
8 8
x = 3
y = -3.5x + 6.5
y = -3.5(3) + 6.5
y = -10.5 + 6.5
y = -4
(x, y) = (3, -4)