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BTW reduction is the action or fact of making a specified thing smaller or less in amount, degree, or size.
Answer:
24.9 L Ar
General Formulas and Concepts:
<u>Atomic Structure</u>
- Reading a Periodic Table
- Moles
- STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
<u>Aqueous Solutions</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
[Given] 40.0 g Ar
[Solve] L Ar
<u>Step 2: Identify Conversions</u>
[PT] Molar Mass of Ar - 39.95 g/mol
[STP] 22.4 L = 1 mol
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Divide/Multiply [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
24.9235 L Ar ≈ 24.9 L Ar
Answer:
Fractional distillation
Explanation:
A method for separating a liquid from a mixture of two or more liquids. ... This method works because the liquids in the mixture have different boiling points. When the mixture is heated, one liquid evaporates before the other.
Answer:
The molar mass of the unknown substance is 255g/mole
Explanation:
Freezing point depression is given by
ΔT = i · Kf · m
Where
m = molality of the solute
i = van't Hoff's factor = i for non electrolyte
Kf = 20.4 °C/m = cryoscopic constant
ΔT = Freezing point depression
Therefore ΔT = 6.6 - 5 = 1.6 °C
1.6 °C = 20.4 °C/m × 1 × m
Therefore m = 1.6/20.4 = 0.0784 m
number of moles in 2.50 g of cyclohexane = 0.0784 m or 0.0784 moles of the substance in 1000 grams of cyclohexane. That is
2.5 ×0.0784/1000 moles in 2.5 graams of cyclohexane that is
1.96 × 10⁻⁵ moles in 2.5 grams of cyclohexane
1.96 × 10⁻⁵ moles of the substance weighs 0.050 grams
Therefore 1 Mole weighs (0.05 g)/(1.96 × 10⁻⁵ moles) = 255g/mole