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3 years ago

HELP IM TIMEDDDDDDDDDDDD

Chemistry

2 answers:

natita [175]3 years ago

6 0

The graphs look most like a desert biome

nadya68 [22]3 years ago

3 0

Answer:

ethier a dessert or a plains

though plains can get rain in the summer

from me living in both

it seems more like a dessert

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Which of these has a higher hydrogen ion concentration? *

Genrish500 [490]

Answer:

pOH = 8.9

Explanation:

pOH+pH = 14

pH= 14- pOH

pOH = 8.9, pH=14-8.9 = 5.1

pOH = 5.5, pH=14-5.5 = 8.5

Than less pH , than more H+ ion concentration.

pH=5.1 <pH=8.5

pH=5.1 is more acidic solution

pH=5.1 or pOH=8.9 has a higher H+ concentration.

8 0

3 years ago

Fill in the chart to identify how scientists represent matter and chemical changes in matter.

ivann1987 [24]

A chemical equation is the symbolic representation of a chemical reaction in the form of symbols and formulae, wherein the reactant entities are given on the left-hand side and the product entities on the right-hand side

A chemical symbol is a notation of one or two letters representing a chemical element

A chemical formula identifies each constituent element by its chemical symbol and indicates the proportionate number of atoms of each element.

3 0

3 years ago

The substances are placed in separate containers at room temperature, and each container is gradually cooled. Which of these sub

Digiron [165]

Answer:

Benzene

Explanation:

You have to find the freezing point for each of these (make sure they're in Celsius). You might want to double check these but:

Benzene: 5.5

Water: 0

Butane: -138

Nitrogen: -210

4 0

3 years ago

Read 2 more answers

Calculate the energy required to heat of ethanol from to . Assume the specific heat capacity of ethanol under these conditions i

Marianna [84]

Answer:

17 kJ

Explanation:

Calculation for the Calculate the energy required to heat 0.60kg of ethanol from 2.2°C to 13.7°C.

Using this formula

q = mC∆T

Where,

q represent Energy

m represent Mass of substance=0.60kg=600g

C represent Specific heat capacity=2.44J·g−1K−1.

∆T represent change in Temperature=2.2°C to 13.7°C.

Let plug in the formula

q=(0.60 kg x 1000 g/kg)(2.44 J/gº)(13.7°C-2.2°C)

q = (600g)(2.44 J/gº)(11.5º)

q=16.836 kJ

q= 17 kJ (Approximately)

Therefore the energy required to heat 0.60kg of ethanol from 2.2°C to 13.7°C will be 17 kJ

5 0

3 years ago

Suppose a group of volunteers is planning to build a park near a local lake. The lake is known to contain low levels of arsenic

ale4655 [162]

A) 10.75 is the concentration of arsenic in the sample in parts per billion .

B) 7,633.66 kg the total mass of arsenic in the lake that the company have to remove.

C)It will take 1.37 years to remove all of the arsenic from the lake.

Explanation:

A) Mass of arsenic in lake water sample = 164.5 ng

The ppb is the amount of solute (in micrograms) present in kilogram of a solvent. It is also known as parts-per million.

To calculate the ppm of oxygen in sea water, we use the equation:

$\text{ppb}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^9$

Both the masses are in grams.

We are given:

Mass of arsenic = 164.5 ng = $164.5\times 10^{-9} g$

$1 ng=10^{-9} g$

Volume of the sample = V = $15.3 cm^3$

Density of the lake water sample ,d= $1.00 g/cm^3$

Mass of sample = M = $d\times V=1.0 g/cm^3\times 15.3 cm^3=15.3 g$

$ppb=\frac{164.5\times 10^{-9} g}{15.3 g}\times 10^9=10.75$

10.75 is the concentration of arsenic in the sample in parts per billion.

Mass of arsenic in $1 cm^3$ of lake water = $\frac{164.5\times 10^{-9} g}{15.3}=1.075\times 10^{-8} g$

Mass of arsenic in $0.710 km^3$ lake water be m.

$1 km^3=10^{15} cm^3$

Mass of arsenic in $0.710\times 10^{15} cm^3$ lake water :

$m=0.710\times 10^{15}\times 1.075\times 10^{-8} g=7,633,660.130 g$

1 g = 0.001 kg

7,633,660.130 g = 7,633,660.130 × 0.001 kg=7,633.660130 kg ≈ 7,633.66 kg

7,633.66 kg the total mass of arsenic in the lake that the company have to remove.

Company claims that it takes 2.74 days to remove 41.90 kilogram of arsenic from lake water.

Days required to remove 1 kilogram of arsenic from the lake water :

$\frac{2.74}{41.90} days$

Then days required to remove 7,633.66 kg of arsenic from the lake water :

$=7,633.66\times \frac{2.74}{41.90} days=499.19 days$

1 year = 365 days

499.19 days = $\frac{499.19}{365} years = 1.367 years\approx 1.37 years$

Company claims that it takes 2.74 days to remove 41.90 kilogram of arsenic from lake water.

Days required to remove 1 kilogram of arsenic from the lake water :

$\frac{2.74}{41.90} days$

Then days required to remove 7,633.66 kg of arsenic from the lake water :

$=7,633.66\times \frac{2.74}{41.90} days=499.19 days$

1 year = 365 days

499.19 days = $\frac{499.19}{365} years = 1.367 years\approx 1.37 years$

It will take 1.37 years to remove all of the arsenic from the lake.

6 0

3 years ago