Answer:
1) 327
2) 3
3) 109
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now I'm not 100% sure #4-6 are correct, but if 4 is right then 5 and 6 are, too.
4) 1074
5) 1074 + 109t
6) 2382
Explanation:
I believe that the answer is B.
Answer:
rise in temperature = 333.53°C
Explanation:
mass of lead bullet, m = 5.9 g
initial velocity, u = 410 m/s
specific heat of lead = 0.126 J/gm - K = 126 J/kg K
Initial kinetic energy of the bullet
K = 1/2 mu^2 = 0.5 x 5.9 x 10^-3 x 410 x 410 = 495.895 J
Half of the kinetic energy is used to raise the temperature of lead bullet
K / 2 = mass of bullet x specific heat of lead x rise in temperature
247.95 = 5.9 x 10^-3 x 126 x rise in temperature
rise in temperature = 333.53°C
Thus, the rise in temperature of lead bullet is 333.53°C.
It gets heavier and heavier