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elena-s [515]
3 years ago
5

When light is reflected by a mirror, the angle of an incidence is always?

Physics
1 answer:
Aliun [14]3 years ago
5 0
It's C, angle of incidence is equal to angle of reflection
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A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent
azamat

The wavelengths of the constituent travelling waves CANNOT be 400 cm.

The given parameters:

  • <em>Length of the string, L = 100 cm</em>

<em />

The wavelengths of the constituent travelling waves is calculated as follows;

L = \frac{n \lambda}{2} \\\\n\lambda = 2L\\\\\lambda = \frac{2L}{n}

for first mode: n = 1

\lambda = \frac{2\times 100 \ cm}{1} \\\\\lambda = 200 \ cm

for second mode: n = 2

\lambda = \frac{2L}{2} = L = 100 \ cm

For the third mode: n = 3

\lambda = \frac{2L}{3} \\\\\lambda = \frac{2 \times 100}{3} = 67 \ cm

For fourth mode: n = 4

\lambda = \frac{2L}{4} \\\\\lambda = \frac{2 \times 100}{4} = 50  \ cm

Thus, we can conclude that, the wavelengths of the constituent travelling waves CANNOT be 400 cm.

The complete question is below:

A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent travelling waves CANNOT be:

A. 400 cm

B. 200 cm

C. 100 cm

D. 67 cm

E. 50 cm

Learn more about wavelengths of travelling waves here: brainly.com/question/19249186

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3 years ago
Which best describes series​
Serjik [45]

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At what minimum speed must a roller coaster be traveling when upside down at the top of a circle so that the passengers do not f
worty [1.4K]

Answer:

v_{min} \approx 17.153\,\frac{m}{s}

Explanation:

The roller coaster begins with maximum kinetic energy and no gravitational potential energy. The gravitational potential energy reaches its maximum when roller coaster is upside down at the top of the circle. The physical model for the roller coaster is constructed by means of the Principle of Energy Conservation:

\frac{1}{2}\cdot m \cdot v_{min}^{2} = m\cdot g \cdot h

The minimum velocity is:

v_{min} = \sqrt{2\cdot g \cdot h}

Let assume that radio of curvature is measured in meters. Hence:

v_{min} = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot(15\,m)}

v_{min} \approx 17.153\,\frac{m}{s}

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Momentum data about the same objects in the same closed system is shown below.
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the value of x is 3.7 because they are arranged in a particular manner.

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