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gladu [14]
3 years ago
9

Resistance to the motion of an automobile consists of road friction, which is almost independent of speed, and air drag, which i

s proportional to speed-squared. For a certain car with a weight of 12000 N, the total resistant force F is given by F = 300 + 1.8v2, with F in newtons and v in meters per second. Calculate the power (in horsepower) required to accelerate the car at 0.96 m/s^2 when the speed is 82 km/h.
Physics
1 answer:
Troyanec [42]3 years ago
6 0

Answer:

73.52983 Hp

Explanation:

m = Mass of car = \dfrac{W}{g}

W = Weight of car = 12000 N

a = Acceleration = 0.96 m/s²

Velocity of the car

v=82\times \dfrac{1000}{3600}\\\Rightarrow v=\dfrac{82}{3.6}\\\Rightarrow v=\dfrac{41}{1.8}

From the question

F=300+1.8v^2\\\Rightarrow F=300+1.8\times \left(\dfrac{41}{1.8}\right)^2\\\Rightarrow F=1233.88\ N

Balancing the forces

\dfrac{P}{v}-1233.88=ma\\\Rightarrow P=(ma+12000)v\\\Rightarrow P=\left(\dfrac{12000}{9.81}\times 0.96+1233.88\right)\dfrac{41}{1.8}\\\Rightarrow P=54853.26055\ W=\dfrac{54853.26055}{746}\\\Rightarrow P=73.52983\ Hp

The power is 73.52983 Hp

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slader Question: A Model Rocket Is Launched Straight Upward With An Initial Speed Of 50m/s. Iit Accelerates With A Constant Upwa
xenn [34]

Answer:

Maximum height reached by the rocket is

y_{max} = 308 m

total time of the motion of rocket is given as

T = 16.44 s

Explanation:

Initial speed of the rocket is given as

v_i = 50 m/s

acceleration of the rocket is given as

a = 2 m/s^2

engine stops at height h = 150 m

so the final speed of the rocket at this height is given as

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v_f = 55.68 m/s

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so we will have

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0 - 55.68^2 = 2(-9.81)(y - 150)

y_{max} = 308 m

Now the total time of the motion of rocket is given as

1) time to reach the height of 150 m

v_f - v_i = at

55.68 - 50 = 2 t

t_1 = 2.84 s

2) time to reach ground from this height

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so total time of the motion of rocket is given as

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How to use Coulomb's law

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Coulomb's law is formulated as follows:

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q₂ is the magnitude of the second charge (in Coulombs),

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