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Neporo4naja [7]
2 years ago
14

Dynamic stretching is a series of movements that warm up the body before an intended activity. Which dynamic stretch would warm

an individual before a one mile run
Physics
1 answer:
Makovka662 [10]2 years ago
8 0

Answer:

They would likely do a whole series of dynamic stretches

Explanation:

It would include warming up the body and then dynamically stretching the lower body, and some upper body as well. This isn't a question with one specific answer

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A ball rolls off a table with a horizontal velocity of 3 m/s. If it takes 0.3 seconds for the ball to reach the floor, how high
LekaFEV [45]

The height of the table above the ground is 0.45 m.

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

  • Horizontal velocity (u) = 3 m/s
  • Time (t) = 0.3 s
  • Acceleration due to gravity (g) = 10 m/s²
  • Height (h) =?

<h3>How to determine the height </h3>

The height of the table can be obtained by using the following formula:

h = ½gt²

h = ½ × 10 × 0.3²

h = 5 × 0.09

h = 0.45 m

Thus, the height of the table is 0.45 m

Learn more about motion under gravity:

brainly.com/question/26275209

6 0
2 years ago
the pull of gravity on mars is 3.7m/s^2. if a astronaut on mars lifts a 10 kg rock 1 m off the ground, just to see whats under i
Elanso [62]
Gravitational potential energy can be calculated using the formula:

PE_{grav} =mgh

Where:
PEgrav = Gravitational potential energy
m= mass
g = acceleration due to gravity
h = height

On Earth acceleration due to gravity is a constant 9.8 but since the scenario is on Mars, the pull of gravity is different. In this case, it is 3.7, so we will use that for g.

So put in what you know and solve for what you don't know. 
m = 10kg
g = 3.7m/s^2
h = 1m

So we put that in and solve it. 
PE_{grav} =mgh
PE_{grav} =(10kg)(3.7m/s^{2})(1m)
PE_{grav} =37J


7 0
3 years ago
What is the approximate wavelength of a light whose first-order bright band forms a diffraction angle of 45.0° when it passes th
max2010maxim [7]

Answer:

its D

Explanation:

edg2020

7 0
3 years ago
Read 2 more answers
A car accelerates uniformly from rest to speed 6.6 m/s in 6.5 s .Find the distance the car travel during this time .​
kirill [66]

Answer:

<em>The distance the car traveled is 21.45 m</em>

Explanation:

<u>Motion With Constant Acceleration </u>

It occurs when an object changes its velocity at the same rate thus the acceleration is constant.

The relation between the initial and final speeds is:

v_f=v_o+at\qquad\qquad [1]

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

The distance traveled by the object is given by:

\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]

Solving [1] for a:

\displaystyle a=\frac{v_f-v_o}{t}

Substituting the given data vo=0, vf=6.6 m/s, t=6.5 s:

\displaystyle a=\frac{6.6-0}{6.5}

a = 1.015\ m/s^2

The distance is now calculated with [2]:

\displaystyle x=0*6.5+\frac{1.015*6.5^2}{2}

x = 21.45 m

The distance the car traveled is 21.45 m

6 0
2 years ago
100 points!!! Please help!!!
Greeley [361]

Answer:

41°

Explanation:

Kinetic energy at bottom = potential energy at top

½ mv² = mgh

½ v² = gh

h = v²/(2g)

h = (2.4 m/s)² / (2 × 9.8 m/s²)

h = 0.294 m

The pendulum rises to a height of  above the bottom.  To determine the angle, we need to use trigonometry (see attached diagram).

L − h = L cos θ

cos θ = (L − h) / L

cos θ = (1.2 − 0.294) / 1.2

θ = 41.0°

Rounded to two significant figures, the pendulum makes a maximum angle of 41° with the vertical.

7 0
3 years ago
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