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3 years ago

What is the weight, in pounds, of a 185-kg object on jupiter? express the weight numerically in pounds?

1 answer:

3 0

Befroe showing a numercial answer, It is necessary to clarify that pounds is not a unit of weight. Pounds is a unit of mass.

Mass is a property of matter which indicates the amount of matter (atoms of certain kind) that the object has. The mass of an object does not change whenever the object changes of environment. It is the same in water, on the air, on Jupiter, the Earth, Venus, the Moon. Any where.

On the other hand, weight is the product of mass times the acceleration of gravity. Therefore, weight is different from mass and it changes depending on the place.

To find the mass in pounds of a 185 kg object, you have to make a conversion of units.

The conversion factor is 1 kg = 2.2046 pounds ⇒ 1 = 2.2046 pounds / kg.

Therefore, 185 kg = 185 kg × 2.2046 pounds / kg = 407.851 pounds = 407.851 lb ← this is the mass in pounds.

To find the weight you had to search for the gravitational acceleration in Jupiter and calcuate it with the formula weight = mass × acceleration of gravity.

You find the value for acceleration of gravity in Jupiter in internet as 24.79 m/s².

Weight = 185 kg × 24.79 /s² = 4,586 kg × m/ s² = 4,586 N.

There is a force unit in disuse called kiloponds. One kilopond equals 9.8 N. Hence, you can convert the weight 4,586 N to kiloponds in this way:

4,586 N × 1 kilopond / 9.8 N ≈ 468 kiloponds or 468,000 ponds ← weight

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Two 10-cm-diameter charged rings face each other, 25.0cm apart. Both rings are charged to +20.0nC. What is the electric field st

Black_prince [1.1K]

Answer:

Part A:

$E_{midpoint}=0$

Part B:

$E_{center}=2711.7558 N/C$

Explanation:

Part A:

Formula of Electric Field Strength:

$E=\frac{1}{4\pi\epsilon}\frac{xQ}{(x^2+R^2)^{3/2}}$

Where:

x is the distance from the ring

R is the radius of the ring

$\epsilon$ is constant permittivity of free space=8.854*10^-12 farads/meter

Q is the charge

For right Ring E at the midpoint can be calculated as:

x for right plate=25/2=12.5 cm=0.125 m

Radius=R=10/2=5 cm=0.05 m

$E_{right}=\frac{1}{4\pi8.854*10^{-12}}\frac{(0.125)*(20*10^{-19})}{((0.125)^2+(0.05)^2)^{3/2}}\\E_{right}=9208.1758 N/C$

For Left Ring E at the midpoint can be calculated as:

Since charge on both plates is +ve and same in magnitude, the electric field will be same for both plates.

$E_{left}=\frac{1}{4\pi8.854*10^{-12}}\frac{(0.125)*(20*10^{-19})}{((0.125)^2+(0.05)^2)^{3/2}}\\E_{left}=9208.1758 N/C$

Electric Field at midpoint:

Both rings have same magnitude but the direction of fields will be opposite as they have same charge on them.

$E_{midpoint}=E_{left}-E_{right}\\E_{midpoint}=9208.1758-9208.1758\\E_{midpoint}=0$

Part B:

At center of left ring:

Due to left ring Electric field at center is zero because x=0.

$E_{left}=\frac{1}{4\pi8.854*10^{-12}}\frac{(0)*(20*10^{-19})}{((0)^2+(0.05)^2)^{3/2}}\\E_{left}=0 N/C$

Due to right ring Electric field at center of left ring:

Now: x=25 cm= o.25 m (To the center of left ring)

$E_{right}=\frac{1}{4\pi8.854*10^{-12}}\frac{(0.25)*(20*10^{-19})}{((0.25)^2+(0.05)^2)^{3/2}}\\E_{right}=2711.7558 N/C$

Electric Field Strength at center of left ring is same as that of right ring.

$E_{center}=2711.7558 N/C$

5 0

3 years ago

Which equation represents an equilibrium system??

MrRissso [65]

A. 2 S O 2, gas, plus O 2, gas, in equilibrium with 2 S O 3, gas.

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3 years ago

At the top of a hill a roller coaster has gravitational potential energy due to its position. What happend to this potential ene

Anuta_ua [19.1K]

As the roller coaster speeds up on the way down the hill, the potential energy of roller coaster will be converted to kinetic energy.

<h3>What is Conservation of Energy ?</h3>

Conservation of energy state that energy is neither created nor destroy, they can only be transformed from one form to another. Energy of and object can transform from Potential energy to kinetic energy and vice versa

Given that at the top of a hill a roller coaster has gravitational potential energy due to its position. What will happen to this potential energy as the roller coaster speeds up on the way down the hill is that the potential energy to the roller coaster will start decreasing while the kinetic energy will start to increase.

The total energy of the roller coaster will be constant because of conservation of energy. As the roller coaster speeds up on the way down the hill, the potential energy will eventually reduce to zero where the total energy of the as the roller coaster will be equal to maximum kinetic energy.

Therefore, as the roller coaster speeds up on the way down the hill, the potential energy of roller coaster will be converted to kinetic energy.

Learn more about Energy here: brainly.com/question/25959744

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1 year ago

With the switch closed, how does the voltage across the 20-ω resistor compare to the voltage across the 10-ω resistor?

jasenka [17]

In electricity, the most famous and basic equation is the Ohm's Law which relates the parameters voltage, current and resistance. One form of this law as written in equation is V = IR, where V is the voltage in volts, I is the current in amperes and R is the resistance in ohms. These parameters depends in the arrangements, whether it's series or parallel.

In a series connection, the voltage is greater across a high-resistance resistor. Therefore, the voltage is much greater for the 20-ohm resistor. However,if it is a parallel circuit, the voltage is just the same for both resistors.

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3 years ago

Examine the lightbulbs in the circuit below. Write a sentence explaining what would happen if lightbulb A burned out. Repeat thi

tatiyna

If the lightbulb A in the circuit shown in the image burned out, the path for the current to flow is disrupted because one of its terminals is connected direct to the source. So, there will be no current through the lightbulbs B, C, and D, and they will turn off. Similarly it will happen, if the lightbulb D burned out.

If the lightbulb B burned out the current will continue circulating through the lightbulbs A, C, and D, because lightbulb B is connected in parallel. Similarly it will happen, if the lightbulb C burned out.

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3 years ago