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Illusion [34]
3 years ago
6

Monochlorination of propane yields two constitutional isomers, and dichlorination yields four. Trichlorination yields five const

itutional isomers. Draw all five trichloropropane isomers.

Chemistry
2 answers:
RSB [31]3 years ago
8 0

Answer:

The trichloro isomers are [figure attached for structures]

a) 1,1,1-trichloropropane

b) 1,1,2-trichloropropane

c) 1,1,3-trichloropropane

d) 1,2,2-trichloropropane

e) 1,2,3-trichloropropane

Explanation:

Constitutional isomers are the compounds with same molecule formula but different arrangements of atoms on the chain.

The monochloro propane isomers are :

a) 1-chloropropane

b) 2-chloropropane

The dichloro isomers are :

a) 1,2-dichloropropane

b) 1,3-dichloropropane

c) 1,1-dichloropropane

d) 2,2-dichloropropane

The trichloro isomers are [figure attached for structures]

a) 1,1,1-trichloropropane

b) 1,1,2-trichloropropane

c) 1,1,3-trichloropropane

d) 1,2,2-trichloropropane

e) 1,2,3-trichloropropane

GaryK [48]3 years ago
6 0
By Tri chlorination, three chlorine atoms can replace the 3 hydrogen atoms in propane molecule to give tri-chlorinated products according to the attached picture.

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Maksim231197 [3]

Answer:

           \large\boxed{\large\boxed{24.6kJ}}

Explanation:

<u>1. Energy to heat the liquid water from 55ºC to 100ºC</u>

     Q=m\times C\times \Delta T

  • m = 10.1g
  • C = 4.18g/JºC
  • ΔT = 100ºC - 55ºC = 45ºC

     Q=10.1g\times 4.18J/g\ºC\times 45\ºC=1,899.81J

<u>2. Energy to change the liquid to steam at 100ºC</u>

      L=\lambda \times n

  • λ = 40.6kJ/mol
  • n = 10.1g / 18.015g/mol = 0.5606mol

      L=40.6kJ/mol\times 0.5604mol=22.76214kJ=22,762.14J

<u>3. Total energy</u>

       1,899.81J+22,762.14J=24,661.95J\approx24,662J\approx24.6kJ

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3 years ago
What kind of property is melting point? an atomic property , , , an atomic property , , a physical property , a physical propert
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2 years ago
An electron is the largest part of an atom. True or False?
IrinaVladis [17]

Answer: False

Explanation:

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3 years ago
Answer the following questions based on the reaction below: NaOH(aq) + KHP(s) --&gt; NaKP(aq)+H2O(I)
Natali [406]

Answer:

<u />

  • <u>a) 1.44g</u>

<u />

  • <u>b) 77.3%</u>

<u />

Explanation:

<u>1. Chemical balanced equation (given)</u>

       NaOH(aq)+ KHP(s)\rightarrow NaKP(aq)+H_2O(l)

<u>2. Mole ratio</u>

1molNaOH(aq):1molKHP(s)

This is, 1 mol of NaOH will reacts with 1 mol of KHP.

<u />

<u>3. Find the number of moles in 72.14 mL of the base</u>

    Molarity=\text{number of moles of solute}/\text{volume of solution in liters}

    \text{Volume of solution}=72.14mL=0.07214liters

     \text{Number of moles of NaOH}=0.0978M\times 0.07214liter=0.007055mol

<u>4. Find the number of grams of KHP that reacted</u>

The number of moles of KHP that reacted is equal to the number of moles of NaOH, 0.007055 mol

Convert moles to grams:

  • mass = number moles × molar mass = 0.007055mol × 204.23g/mol
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You have to round to 3 significant figures: 1.44 g (because the molarity is given with 3 significant figures).

<u>5. Find the percentage of KHP in the sample</u>

The percentage is how much of the substance is in 100 parts of the sample.

The formula is:

  • % = (mass of substance / mass of sample) × 100

  • % = (1.4408g/ 1.864g) × 100 = 77.3%
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Please help I will give brainliest.
iris [78.8K]

Answer:

the second one looks like it so I picked the second one

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