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Andru [333]
2 years ago
15

2B + 3H2 2BH3 How many moles of BH3 are synthesized when 27.0 moles of H2 completely react?

Chemistry
1 answer:
STatiana [176]2 years ago
3 0

Answer: 18.0 moles of BH_3 will be produced when 27.0 moles of H_2 completely react.

Explanation:

The balanced chemical equation is:

2B+3H_2\rightarrow 2BH_3  

According to stoichiometry :

3 moles of H_2 produce = 2 moles of BH_3

Thus 27.0 moles of H_2 will produce=\frac{2}{3}\times 27.0=18.0 moles  of BH_3

Thus 18.0 moles of BH_3 will be produced when 27.0 moles of H_2 completely react.

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Answer:

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A sample of gas occupies a volume of 73.7 mL. As it expands, it does 133.7 J of work on its surroundings at a constant pressure
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7 0
3 years ago
What is the molality of a solution containing 10.0 G of NA2 S04 and 1000.0 G of water
galina1969 [7]

Explanation:

1 literThe total of water is equal to 1000.0 g of water

we need to find the molality of a solution containing 10.0 g of dissolved in  Na₂S0₄1000.0 g of water

1. For that find the molar mass

Na:  2 x 22.99= 45.98

S:  32.07

O:  4 x 16= 64

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We have to find the number of moles, y

To find the number of moles divide 10.0g by 142.05 g/mol.

So the number of moles is 0.0704 moles.

For the molarity, you need the number of moles divided by the volume. So, 0.0704 mol/1 L.

The molarity would end up being 0.0704 M

The molality of a solution containing 10.0 g of Na2SO4 dissolved in 1000.0 g of water is  0.0704 Mliter

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2 years ago
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6 0
3 years ago
Read 2 more answers
What mass of propane could burn in 48.0 g of oxygen? C3H8 + 5O2 → 3CO2 + 4H2O
Ipatiy [6.2K]

Answer:

Mass = 13.23 g  

Explanation:

Given data:

Mass of oxygen = 48.0 g

Mass of propane burn = ?

Solution:

Chemical equation:

C₃H₈ + 5O₂     →      3CO₂ + 4H₂O

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 48.0 g/ 32 g/mol

Number of moles = 1.5 mol

now we will compare the moles of propane and oxygen.

              O₂           :          C₃H₈

               5            :            1

             1.5            :          1/5×1.5 = 0.3 mol

Mass of propane burn:

Mass = number of moles × molar mass

Mass = 0.3 mol × 44.1 g/mol

Mass = 13.23 g  

6 0
3 years ago
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