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3 years ago

2B + 3H2 2BH3 How many moles of BH3 are synthesized when 27.0 moles of H2 completely react?

Chemistry

1 answer:

STatiana [176]3 years ago

3 0

Answer: 18.0 moles of $BH_3$ will be produced when 27.0 moles of $H_2$ completely react.

Explanation:

The balanced chemical equation is:

$2B+3H_2\rightarrow 2BH_3$

According to stoichiometry :

3 moles of $H_2$ produce = 2 moles of $BH_3$

Thus 27.0 moles of $H_2$ will produce= $\frac{2}{3}\times 27.0=18.0 moles$ of $BH_3$

Thus 18.0 moles of $BH_3$ will be produced when 27.0 moles of $H_2$ completely react.

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N₂ + 3H₂ ⇒ 2NH₃
1mol : 3mol : 2mol
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3 years ago

For a particular redox reaction, NO-2 is oxidized to NO-3 and Ag+ is reduced to Ag . Complete and balance the equation for this

Salsk061 [2.6K]

The following are the steps to complete and balnce the equation for the given reaction

<u>Explanation:</u>

We are given, NO2– is oxidized to NO3– and Ag is reduced to Ag

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Step 1) Assign the oxidation state to each element reaction

NO2– + Ag+ -----> NO3– + Ag(s)

N= +3 N = +5

O = -2 O = -2

Ag = +1 Ag = 0

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Ag+ -----> Ag(s) ……….reduction half reaction

Step 2) Balance the element other than O and H

NO2– -----> NO3–

Ag+ -----> Ag(s)

Step 3) Balance the O by adding 1 H2O for 1 O

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Step 4) Balance the H by adding H+

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Ag+ -----> Ag(s)

Step 5) Balance the charge by adding electron

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Step 6) Balance the electron in both half reaction

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B) Simple Distillation

C) Evaporation

D) Sublimation

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Explanation:

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