Solving this using the time, we know that range = horizontal velocity x time of flight
since
there are no horizontal forces acting on the ball, there are no
horizontal accelerations and the initial horizontal velocity of 36 cos
28 will be constant throughout. If we use the correct time of flight given the launch parameters, we have
range = 36 cos 28 x 3.44 s = 109.3 m
So, basically, it might have different quantities, such as Carbon Dioxide (CO2) and Carbon Monoxide (CO), which are both made up of Carbon and Oxygen, but Carbon Monoxide has less oxygen. And they both have different properties, like CO is poisonous.
A unit of acceleration needs a unit of length in the numerator
and a squared unit of time in the denominator.
Example: meters / second²
feet / minute²
smoots / hour²
furlongs / fortnight² .
Ideally, in order to completely describe an acceleration vector,
you also need to state a direction.
Answer:
2.36 x 10^6 J
Explanation:
Tc = 0°C = 273 K
TH = 22.5°C = 295.5 K
Qc = heat used to melt the ice
mass of ice, m = 85.7 Kg
Latent heat of fusion, L = 3.34 x 10^5 J/kg
Let Energy supplied is E which is equal to the work done
Qc = m x L = 85.7 x 3.34 x 10^5 = 286.24 x 10^5 J
Use the Carnot's equation
QH = 309.8 x 10^5 J
W = QH - Qc
W = (309.8 - 286.24) x 10^5
W = 23.56 x 10^5 J
W = 2.36 x 10^6 J
Thus, the energy supplied is 2.36 x 10^6 J.
