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Luda [366]
2 years ago
13

Decribir los tejidos que forman en triceps, gluteo, deltroides. ​

Physics
1 answer:
Genrish500 [490]2 years ago
7 0

Answer:The deltoid is a muscle in the shoulder It has the shape of a hollow semi-cone

Explanation:

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Why is carbon added to iron
swat32

Answer:

it transforms it into high carbon alloy that is harder and can be sharper but is also more brittle in the process.

Explanation:

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3 years ago
You are the Engineering Duty Officer getting your submarine, the USS GREENVILLE, ready to put to sea. When nuclear material in t
podryga [215]

Answer:

Super-critical mass

Explanation:

This term refers to the mass, in which the amount of fission processes per unit of time increases to the point, where some intrinsic feedback mechanism causes the reactor to reach an equilibrium point at a high temperature or power, that is, It becomes critical again, or it is destroyed due to the amount of processes.

7 0
3 years ago
6. A child tugs on a rope attached to a 0.62-kg toy with a horizontal force
ser-zykov [4K]

Answer:

Explanation:

Force Mass * acceleration

F = ma

a = F/m

Sum of force = 16.3N - 15.8N = 0.5N

Mass = 0.62kg

Substitute

a = 0.5/ * 0.62

a = 0.81m/s²

The acceleration of the toy is 0.81m/s²

8 0
3 years ago
What are compounds considered to be
bija089 [108]

Answer:A compound is a substance formed when two or more elements are chemically joined.

Explation:Water, salt, and sugar are examples of compounds.

I hope this helps<3

7 0
2 years ago
Two long parallel wires are separated by forty centimeters and carry oppositely-directed currents of ten amperes. Find the magni
Softa [21]

Answer:

1.04μT

Explanation:

Due to both wires have opposite currents, the magnitude of the total magnetic field is given by

B_T=\frac{\mu_o I}{2 \pi r_1}-\frac{\mu_o I}{2 \pi r_2}

I: electric current = 10A

mu_o: magnetic permeability of vacuum = 4pi*10^{-7} N/A^2

r1: distance from wire 1 to the point in which B is measured.

r2: distance from wire 2.

The distance between wires is 40cm = 0.4m. Hence, r1=0.2m r2=0.6m

By replacing in the formula you obtain:

B_T=\frac{(4\pi *10^{-7}N/A^2)(10A)}{2\pi}(\frac{1}{0.4m}-\frac{1}{0.6m})=1.04*10^{-6}T =1.04\mu T

hence, the magnitude of the magnetic field is 1.04μT

4 0
3 years ago
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