According to Newton's third law
- Ever action has a equal and opposite reaction.
So

- Hence if applied force is 8000N opposing force is also 8000N
As car is pushed forward so the opposing force is less than 8000N
P=4800kgm/s
As
p=mΔv
where p is momentum, m is mass and v is velocity
Given values is
m =1200kg
Δv= 17m/s-13m/s=4m/s
Now
p=mΔv
p=(1200kg)*(4m/s)
p=4800kgm/s
Answer:
10N
Explanation:
The formula for calculating the resultant is expressed as;
R = √F1²+F2²
F1 and F2 are the forces
Given
F1 = 6.0N
F2 = 8.0N
R = √6²+8²
R = √36+64
R = √100
R = 10.0N
Hence the magnitude of the net force is 10N