Answer:
11.962337 × 10^-4 N
Explanation:
Given the following :
Length L = 11.8
Charge = 29nC = 29 × 10^-9 C
Linear charge density λ = 1.4 × 10^-7 C/m
Radius (r) = 2cm = 2/100 = 0.02 m
Using the relation:
E = 2kλ/r ; F =qE
F = 2kλq/L × ∫dr/r
F = 2*k*q*λ/L × (In(0.02 + L) - In(0.02))
2*k*q*λ/L = [2 × (9 * 10^9) * (29 * 10^9) * (1.4 * 10^-7)]/ 0.118] = 6193.2203 × 10^(9 - 9 - 7) = 6193.2203 × 10^-7 = 6.1932203 × 10^-4
In(0.02 + 0.118) - In(0.02) = In(0.138) - In(0.02) = 1.9315214
Hence,
(6.1932203 × 10^-4) × 1.9315214 = 11.962337 × 10^-4 N
A = dv/dt = ak
ak = ( 0.0 m/s - 9.0 m/s ) / ( 3 s )
3m/s^2
the atomic number of a chemical element (also known as its proton number) is the number of protons found in the nucleus of an atom of that element, and therefore identical to the charge number of the nucleus.
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D.) White Dwarf
It is the smallest star whose mass is approximately equal or greater than 1.4M
Here, M = mass of the Sun.
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The final temperature of the mixture is closest to 32.5 °C
<h3>Data obtained from the question</h3>
- Mass of warm water (Mᵥᵥ) = 50 g
- Temperature warm water (Tᵥᵥ) = 40 °C
- Mass of cold water (M꜀) = 30 g
- Temperature of cold water (T꜀) = 20 °C
- Specific heat capacity of the water = 4.184 J/gºC
- Equilibrium temperature (Tₑ) =?
<h3>How to determine the equilibrium temperature </h3>
Heat loss = Heat gain
MᵥᵥC(Tᵥᵥ – Tₑ) = M꜀C(Tₑ – M꜀)
50 × 4.184 (40 – Tₑ) = 30 × 4.184(Tₑ – 20)
209.2(40 – Tₑ) = 125.52(Tₑ – 20)
Clear bracket
8368 – 209.2Tₑ = 125.52Tₑ – 2510.4
Collect like terms
8368 + 2510.4 = 125.52Tₑ + 209.2Tₑ
10878.4 = 334.72Tₑ
Divide both side by 334.72
Tₑ = 10878.4 / 334.72
Tₑ = 32.5 °C
Learn more about heat transfer:
brainly.com/question/6363778
