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balandron [24]
4 years ago
11

What is a star called that dies peacefully​

Physics
2 answers:
Setler [38]4 years ago
6 0

Answer:

This type of star is called the "white dwarf." When a very massive star exhausts its nuclear fuel it explodes as a supernova.

Hope it helps

uranmaximum [27]4 years ago
5 0

Answer:

A White Dwarf

Explanation:

It starts by cooling and then it will die peacefully.

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1. If a radioactive sample has a half-life one month, how much of the original sample will be left at the end of
evablogger [386]

Answer:

second month = 0.5² = 1/4 of original

third month = 0.5³ = 1/8 of original

Explanation:

4 0
3 years ago
Pls help with either of these I will give up brainliest
Contact [7]

Answer:

1. The bird close to the center

2. 4/25 of the original force.

Explanation:

1. Tangential velocity is v=w*d (in m/s), where w is the rotational speed, commonly denoted as the letter omega (in radians per second). d is the distance from the center of the rotating object to the position of where you would like to calculate the velocity (in meters).

As we can note, the furthest from the center we are calculating the velovity the higher it is, because the rotational velocity is not changing but the distance of the object with respect to the center is. If v=w*d, then the lower the d (distance) the lower the tangential velocity.

2. Take a look at the picture:

We have the basic equation for the gravitational force.

We have to forces: Fg1, which is the original force, and Fg2, the force when the mass and the distance changes.

If we consider that mass 2 didn't change (m2'=m2), mass 1 is four times its original (m1'=4*m1) and distance is 5 times the original (r'=5*r), then next step is just plugging it into the equation for Fg2.

Dividing the original force Fg1 by the new force Fg2 (notice you can just as well do the inverse, Fg2 divided by Fg1) gives us the relation between the forces, cancelling all the variables and being left only with a simple fraction!

6 0
3 years ago
Que aceleración adquiere un cuerpo de 0.5 kg cuando actúa una fuerza n2​
san4es73 [151]
La aceleración que adquiere el cuerpo de 0.5Kg es:
5 0
3 years ago
A very long thin wire carries a uniformly distributed charge, which creates an electric field. The electric field is (2300 N/C ,
Leto [7]

Answer:

λ= 5.24 × 10 ⁻² nC/cm

Explanation:

Given:

distance r = 4.10 cm = 0.041 m

Electric field intensity E = 2300 N/C

K = 9 x 10 ⁹ Nm²/C

To find λ = linear charge density = ?

Sol:

we know that E= 2Kλ / r

⇒ λ = -E r/2K         (-ve sign show the direction toward the wire)

λ = (- 2300 N/C × 0.041 m) / 2 ×  9 x 10 ⁹ Nm²/C

λ = 5.24 × 10 ⁻⁹ C/m

λ = 5.24 nC/m = 5.24 nC/100 cm

λ= 5.24 × 10 ⁻² nC/cm

3 0
3 years ago
A tightrope walker wants to know the tension used to support the rope that is suspended between two poles. The rope is 18 m long
Alla [95]

Answer:

T = 29.6 N

Explanation:

length of the rope is

L = 18 m

mass of the rope is

m = 12 kg

now we have

mass per unit length of the rope is given as

[te]\lambda = \frac{12 kg}{18 m}[/tex]

now time taken by wave to reach from end to other

t = \frac{L}{v}

2.7 s = \frac{18}{v}

v = 6.67 m/s

now we have

v = \sqrt{\frac{T}{\lambda}}

6.67 = \sqrt{\frac{T}{0.67}}

so we will have

T = 29.6 N

5 0
4 years ago
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