Question

Nitrogen at an initial state of 300 K, 150 kPa, and 0.2 m3is compressed slowly in an isothermal process to a final pressure of 800 kPa. Determine the work done during this process.

Answer 1

Answer:

$W=-251096.465\ J$ negativesign denotes thatthe work is consumed by the system.

Explanation:

Given:

Isothermal process.

initial temperature, $T_1=300\ K$

initial pressure, $P_1=150kPa$

initial volume, $V_1=0.2\ m^3$

final pressure, $P_2=800\ kPa$

The work done during an isothermal process is given by:

$W=P_1.V_1\times ln(\frac{P_1}{P_2} )$

$W=150\times 1000\times \ln\frac{150}{800}$

$W=-251096.465\ J$ negativesign denotes thatthe work is consumed by the system.