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3 years ago

I dont know how to do these questions I would be pleased if someone helped thankyou.

Mathematics

1 answer:

sleet_krkn [62]3 years ago

5 0

Area = area of the square in the center + 2 * area of the 2 quarter circles.

= 5^2 + 2 * 1/4 *3.14 * 5^2

= 25 + 39.25

= 64.3 in^2 answer

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(87/4) / (5/2) =
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3 years ago

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3 years ago

Jose asks his friends to guess the higher of two grades he received on his math tests. He gives them two hints. The difference o

AlekseyPX

Answer : 96

x – y = 16 --------> equation 1

$\frac{1}{8} x +\frac{1}{2} y = 52$

x is the higher grade and y is the lower grade

We solve the first equation for y

x - y = 16

-y = 16 -x ( divide each term by -1)

y = -16 + x

Now substitute y in second equation

$\frac{1}{8} x +\frac{1}{2} ( -16 + x ) = 52$

$\frac{1}{8} x - 8 + \frac{1}{2} x = 52$

$\frac{1}{8} x + \frac{1}{2} x - 8 = 52$

Take common denominator to combine fractions

$\frac{1}{8} x + \frac{4}{8} x -8 = 52$

$\frac{5}{8} x - 8 = 52$

Add 8 on both sides

$\frac{5}{8} x = 60$

Multiply both sides by $\frac{8}{5}$

x = 96

We know x is the higher grade

96 is the higher grade of Jose’s two tests.

6 0

3 years ago

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