In which century was the DNA database established?
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To place the poles of a 1. 5 v battery to achieve the same electric field is 1.5×10−2 m
The potential difference is related to the electric field by:
∆V=Ed
where,
∆V is the potential difference
E is the electric field
d is the distance
what is potential difference?
The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other.
We want to know the distance the detectors have to be placed in order to achieve an electric field of
E=1v/cm=100v/cm
when connected to a battery with potential difference
∆v=1.5v
Solving the equation,we find
learn more about potential difference from here: brainly.com/question/28166044
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Answer:
(a). The decay constant is
The half life is 11.3 hr.
(b). The value of N₀ is
(c). The sample's activity is 1.87 mCi.
Explanation:
Given that,
Activity
Time
Activity R= 8 mCi
(a). We need to calculate the decay constant
Using formula of activity
Put the value into the formula
We need to calculate the half life
Using formula of half life
Put the value into the formula
(b). We need to calculate the value of N₀
Using formula of
Put the value into the formula
(c). We need to calculate the sample's activity
Using formula of activity
Put the value intyo the formula
Hence, (a). The decay constant is
The half life is 11.3 hr.
(b). The value of N₀ is
(c). The sample's activity is 1.87 mCi.