2 years ago

A vertical spring (ignore its mass), whose spring constant is 1070 N/m, is attached to a table and is compressed 0.100 m.

Physics

1 answer:

harina [27]2 years ago

3 0

I can not solve the problem if I do not have the mass.

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According to newtos first law of motion. what is required to make a object slow down.

ladessa [460]

Answer:

Friction

Explanation:

Friction is a force that slows down moving objects. If you roll a ball across a shaggy rug, you can see that there are lumps and bumps in the rug that make the ball slow down. The rubbing, or friction, between the ball and the rug is what makes the ball stop rolling. External Force is required.

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3 years ago

You toss a bowling ball straight up into the air with a speed of 2.1 m/s. How long does it take the bowling ball to reach its hi

lara [203]

Time taken by the bowling ball to reach its highest point= 0.214 s

initial velocity= Vi=2.1 m/s

Final velocity= Vf=0 as the velocity at the highest point is zero.

acceleration= g= -9.8 m/s²

using the kinematic equation Vf= Vi + at

0= 2.1 + (-9.8)t

t= -2.1/-9.8

t=0.214 s

Thus the time taken by the bowling ball to reach its highest point is 0.214 s

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3 years ago

The tendency for an object at rest to remain at rest

Zarrin [17]

Inertia is the force in play here

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2 years ago

Ben's famliy lives in Florida. His dad wants to cut down the cost of the electricity bill, and he has decided to install some la

AlexFokin [52]

Answer:

the answer would be solar energy, because solar panels are used for solar energy and they also cut back on your bill

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2 years ago

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In the ENGR 10 lab (E391), there are 50 long light bulbs (P=100 W) and 30 regular bulbs (P=60 W). How much energy is consumed li

Alenkinab [10]

Answer:

Total energy saving will be 0.8 KWH

Explanation:

We have given there are 50 long light bulbs of power 100 W so total power of 50 bulb = 100×50 = 5000 W = 5 KW

30 bulbs are of power 60 W

So total power of 30 bulbs = 30×60 = 1800 W = 1.8 KW

Total power of 80 bulbs = 1.8+5 = 6.8 KW

Total time = 3 hour

We know that energy $E=power\times time=6.8\times 3=20.4KWH$

Now power of each CFL bulb = 25 W

So power of 80 bulbs = 80×25 = 2000 W = 2 KW

Energy of 80 bulbs = 2×3 = 6 KWH

So total energy saving = 6.8-6 = 0.8 KWH

6 0

3 years ago