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3 years ago

How can one explain the fact that nearly all other galaxies appear to be moving farther away from us?

2 answers:

6 0

How can one explain the fact that nearly all other galaxies appear to be moving farther away from us?


a) the universe is expanding

juin [17]3 years ago

4 0

A) the universe is expanding
Every galaxy is moving away from each other - not just us. And the further they are away, the faster they are moving

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A volleyball player bumps a ball across a net with the velocity and angle shown below. What is the maximum height of the ball?

Marrrta [24]

Answer:

D. 12.4 m

Explanation:

Given that,

The initial velocity of the ball, u = 18 m/s

The angle at which the ball is projected, θ = 60°

The maximum height of the ball is given by the formula

h = u² sin²θ/2g m

Where,

g - acceleration due to gravity. (9.8 m/s)

Substituting the values in the above equation

h = 18² · sin²60 / 2 x 9.8

= 18² x 0.75 / 2 x 9.8

= 12.4 m

Hence, the maximum height of the ball attained, h = 12.4 m

6 0

3 years ago

1.Narysuj obraz ołówka o długości 6 cm znajdującego się w odległości 8 cm od soczewki o ogniskowej 6 cm

Aliun [14]

Answer:

free quotes from carpet repair contractors at door in

Explanation:

india is the most powerful and I have seen a great deal in hindi for girl in a world of sentence since the poem was a novel that led

5 0

3 years ago

Which region of the country would be considered the most heavily religious

fgiga [73]

i would guess the national religon

8 0

4 years ago

write a hypotheses about the use of an objects physical charecteristics to determine its density use the format "if then because

JulijaS [17]

i don't know.

Explanation:

because i don't want responde

6 0

2 years ago

If the block is subjected to the force of F = 500 N, determine its velocity at s = 0.5 m. When s = 0, the block is at rest and t

STatiana [176]

Answer:

The velocity is $4.6 m/s^2$

Explanation:

Given:

Force = 500N

Distance s= 0

To find :

Its velocity at s = 0.5 m

Solution:

$\sum F_{x}=m a$

$F\left(\frac{4}{5}\right)-F_{S}=13 a$

$500\left(\frac{4}{5}\right)-\left(k_{s}\right)=13 a$

$400-(500 s)=13 a$

$a = \frac{400 -(500s)}{13}$

$a = (30.77 -38.46s) m/s^2$

Using the relation,

$a=\frac{d v}{d t}=\frac{d v}{d s} \times \frac{d s}{d t}$

$a=v \frac{d v}{d s}$

$v d v=a d s$

Now integrating on both sides

$\int_{0}^{v} v d v=\int_{0}^{0.5} a d s$

$\int_{0}^{v} v d v=\int_{0}^{0.5}(30.77-38.46 s) d s$

$\left[\frac{v^{2}}{2}\right]_{0}^{2}=\left[\left(30.77 s-19.23 s^{2}\right)\right]_{0}^{0.5}$

$\left[\frac{v^{2}}{2}\right]=\left[\left(30.77(0.5)-19.23(0.5)^{2}\right)\right]$

$\left[\frac{v^{2}}{2}\right]=[15.385-4.807]$

$\left[\frac{v^{2}}{2}\right]=10.578$

$v^{2}=10.578 \times 2$

$v^{2}=21.15$

$v = \sqrt{21.15}$

$v = 4.6 m/s^2$

8 0

3 years ago