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NeTakaya
3 years ago
10

How can one explain the fact that nearly all other galaxies appear to be moving farther away from us?

Physics
2 answers:
Leokris [45]3 years ago
6 0
<span>How can one explain the fact that nearly all other galaxies appear to be moving farther away from us?

</span>
<span>a) the universe is expanding

</span>
juin [17]3 years ago
4 0
A) the universe is expanding
Every galaxy is moving away from each other - not just us. And the further they are away, the faster they are moving
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A vector points -43.0 units
Naddika [18.5K]

Answer:

Explanation:

To find the direction of this vector we need o find the angle that has a tangent of the y-component over the x-component:

tan^{-1}(\frac{11.1}{-43.0})=-14.5 but since we are in Q2 we have to add 180 degrees to that angle giving us 165.5 degrees

8 0
3 years ago
A baseball pitcher throws a 0.14 kg ball toward a batter who is 18 m away.
Olin [163]

Answer:

A. 112 J

Explanation:

KE = ½mv² = ½(0.14)40² = 112 J

5 0
3 years ago
if a bus has a mass of 5000 kg and a velocity of 10 m/s, what must the velocity of a 1500 kg can be to have the same momentum
fgiga [73]

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6 0
3 years ago
It takes 20 N of force to move a box a distance of 10 m. How much work is done on the box?
PIT_PIT [208]

Answer:

Ans is 200 J

Explanation:

Given:  Force = 20N

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Work done  = Force * displacement

                    =  20 * 10

                    =  200 J

3 0
3 years ago
A body of mass 2 kg is moving in the positive X-Direction with a speed of 4 m/s collides head on with an another body of mass 3
Inga [223]
m_1=2 \\ m_2=3 \\ v_1=4 \\ v_2=1 \\ v\text{ =speed after collision (to be determined)}.

The momentul of the system preserves:

m_1v_1-m_2v_2=(m_1+m_2)v \ \ \ \ \ \Rightarrow \ \ \ \ \ v=\dfrac{m_1v_1-m_2v_2}{m_1+m_2}.

Ok, we found the speed after the collision.
Now, because the impact is plastic, it produces heat, sound energy and who knows what other forms of energy. We denote all this wasted energy with E.

Now, we write the energy conservation law:

\dfrac{m_1v_1^2}{2}+\dfrac{m_2v^2_2}{2}=\dfrac{(m_1+m_2)v^2}{2}+E

From the above equation, you find E,  and then conclude that the sound energy can certainly not be greater than this.
8 0
3 years ago
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