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Oduvanchick [21]
3 years ago
9

You then measure Polly's internal temperature to be 13°C, which is quite a drop from the normal human body temperature of 37°C.

And weighing Polly, you find her mass to be 60 kg. Now, subtracting the heat warming the water from the surrounding environment, we assume Polly gave up only 5000 kJ of thermal energy to warm the bath. With these numbers, determine Polly's specific heat in units J/(kg°C)_______.
Physics
1 answer:
Firlakuza [10]3 years ago
4 0

Using the expression to find the Heat exchange energy, we can find the required value for the Poly's specific heat in its respectively units. Matematically this can be expressed as,

Q = mC_p \Delta T

Where,

m = Mass

C_p= Specific heat

\Delta T= Change in temperature

Q = Heat change

Re-arrange to find the specific heat we have that

C_p = \frac{Q}{m\Delta T}

C_p = \frac{5000*10^3}{60(37-13)}

C_p = 3472.22J/kg\cdot \°C

Therefore the Polly's specific heat is 3472.22J/kg\cdot \°C

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Answer:

The tension on the string is  T  =  43.302 \ N

Explanation:

From the question we are told that

    The mass of the rock is m_r = 5.00 \ kg =  5000 \ g

       The density of the rock is \rho  =  4300 \ kg/m^3 =  4.3 g/dm^3

       

Generally the volume of the rock is mathematically evaluated as

          V    =  \frac{m_r}{\rho}

substituting values

        V    =  \frac{5000}{4.3}

       V    =  1162.7 \  dm^3

The volume of the rock immersed in water is

      V_w = \frac{V}{2}  

substituting values

     V_w = \frac{1162.7 }{2}

     V_w = 581.4 \ dm^3

mass of water been displaced by the this volume is

     m_w  = V_w     According to Archimedes principle

=>   m_w =  581.4 \ g

     m_w =  0.5814 \ kg

The weight of the water displace is  

      W _w =  m_w  * g

      W _w =  0.5814  * 9.8

      W _w = 5.698 \ N

The actual weight of the rock is  

      W_r  =  m_r * g

     W_r  =  5.0 *  9.8

     W_r  =  49.0 \ N

The tension on the string is

       T  = W_r - W_w

substituting values

       T  = 49.0 -  5.698

       T  =  43.302 \ N

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