Answer:
shaft is not transform 100% power
Explanation:
given data
current = 10 amp
voltage = 110 v
torque = 10.2 Nm
rotating speed N = 1000 rpm
solution
we get here first power that is consume by motor is express as
power = current × voltage .........1
power = 10 × 110
power = 1100 W
and power that transmit by shaft is express as
power = T × ω
power = T ×
power = 10.2 ×
power = 1068.14 W
so we can say from above both power
shaft is not transform 100% power
The size conductor that should be used to supply each motor is 12 AWG and the size conductor that should be used for the feeder conductor is 1/0AWG.
<h3>Size conductor</h3>
a. Using NEC table 430.250
Running connect for 150HP connected to 460V = 21 A
Conductor size=25% current to 125% current (Increase)
Increase current=21×125/100
Increase current=26.25 A
Nearest standard conductor size using NEC table 310.15(B)(16)=25 A
Since the motor contain NEMA design code the conductor will be choosing from 75° column which means that the size conductor that should be used to supply each motor is 12AWG copper conductors.
b. Feeder conductor
Using NEC section 430.24 plus ampere rating of other motors
Running current
Using NEC Table 430.250
Running current=26.25+21+21+21+21+21
Running current=131.25 A
The value that is greater than 131.25 A under 75° column of NEC Table 310 (B)(16) is 150 A which means that the size conductor that should be used for the feeder conductor is 1/0 AWG conductors.
Therefore the size conductor that should be used to supply each motor is 12 AWG and the size conductor that should be used for the feeder conductor is 1/0AWG.
Learn more about size conductor here: brainly.com/question/14825264
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Answer:
The flow velocity reduces to 0.72 m/s
Explanation:
According to the equation of continuity discharge in the channel should remain same
Thus we have
For a rectangular channel we have
Applying values in the continuity equation and since the width of the channel remains constant 3.0 m we have