Why is psychology considered a science
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Answer:
provide 180 mm spacing
Explanation:
GIVEN DATA
rectangular beam: (b) = 300 mm, (d) = 575 mm
reinforced for flexure = 4Ф32 bars
WD = 30 kN /m, WL = 45 kN/m
Wu = 1.4 * 30 + 1.6 * 45 = 114 kN/m
i) concrete shear stress ( vc)
100 Ac / bd = (100 * u * * 32^2) / 300 * 575 = 1.865
from table 3.8
when: 100 Ac / bd = 1.865 then Vc = 0.778 N/mm^2
Ultimate shear force = (114 *5.5) / 2 = 313.5 kN
design shear stress = V / bd = (313.5 * 10^3) / (300 * 575) = 1.82 N/mm^2
v < 0.8 = 1.82 < 3.75
design link provided according to
Asv / sv = b(v-vc) / 0.87 fy = 300(1.82 - 0.778) / 0.87 (420)
ASv / Sv = 0.855
From table 3.13 :the value of Asv / sv can be calculated as
x = (-25) [ 0.625] + 200 = 184.375 mm
provide 180 mm spacing
Work, W = 277.269kJ
Internal energy, Q = 277.269kJ
<u>Explanation:</u>
Given-
Pressure, P1 = 2 bar
Temperature, T1 = 300K
Volume, V1 = 2m³
P2 = 1 bar
PV = constant
Let,
mass in kg be m
Work in kJ be W
Heat transfer in kJ be Q
R' = 8.314 kJ/kmolK
Mass of air, Mair = 28.97 kg/kmol
R = 0.289 kJ/kgK
We know,
PV = mRT
m = 5.65kg
To calculate V₂:
PV = constant = P₁V₁ = P₂V₂
P₁V₁ = P₂V₂
V₂ = 4m³
To calculate the work:
P₁V₁ = C
P₁ = C/ V₁
where limit is V₁ to V₂
To calculate heat transfer:
Q - W = Δu
Q - W = m (u₂ - u₁)
Q = W + m (u₂ - u₁)
Q = W + m X cv X (T₂ - T₁)
Since, T₁ ≈ T₂
There is no change of internal energy.
W = Q
Q = 277.269kJ
Answer:
a) see attachment
b) A= m0m1+ m1m2+ m0m2
see attachment for K-map
c) see attachment
Explanation:
a) see attachment for truth table
b) see attachment for k-map
A= m0m1+ m1m2+ m0m2
c) see attachment for gate level circuit
