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max2010maxim [7]
3 years ago
14

A 3-m wide rectangular channel has a flow velocity of 1.8 m/s when the depth of flow is 1.2 m. what will be the flow velocity wh

en the depth of flow is increased to 3 m?
Engineering
1 answer:
valina [46]3 years ago
6 0

Answer:

The flow velocity reduces to 0.72 m/s

Explanation:

According to the equation of continuity discharge in the channel should remain same

Thus we have

A_{1}V_{1}=A_{2}V_{2}

For a rectangular channel we have Area=Depth\times Width

Applying values in the continuity equation and since the width of the channel remains constant 3.0 m we have

3\times 1.8\times 1.2=3\times 3\times V_{2}\\\\\therefore V_{2}=\frac{6.48}{9}=0.72m/s

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Answer:

W = 2695.14 lb

Explanation:

given,

side of cube = 3 ft

density of the cube = 3.1 slugs/ft³

we know,

density = \dfrac{mass}{volume}

mass = density x volume

volume = 3³ = 27 ft³

mass =  3.1  x 27

    m = 83.7 slugs.

weight calculation

converting mass from slug to pound

weight of 1 slug is equal to 32.2 lb

now,

weight of the cube is equal to

  W = 83.7 slugs x 32.2 lb/slug

  W = 2695.14 lb

hence, weight is equal to W = 2695.14 lb

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Answer:

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Explanation:

Solution

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