There are 63 students in the room, this is because 21 time 3 gives you 63.
<span>If A = James's present age
then
</span><span>his age seven years from now = A - 7
hope it helps</span>
Based on the 5 trials, 1 carton of eggs is expected to contain at least one broken egg, on average
<h3>How to determine the number of cartons</h3>
From the question, we understand that only one of the first 10 double-digit numbers is between 01 and 08
This means that:
The average carton or the expected value of eggs in the simulation is 1
Hence, 1 carton of eggs is expected to contain at least one broken egg, on average
Read more about expected values at:
brainly.com/question/15858152
There isnt one its has to be consistent but honestly idk
Step-by-step explanation:
ah, here you go.
come on, now. you know this now ...
again, mutually exclusive attributes in the table (no overlap here) allow us to add the numbers for a total :
4+2+12+10 = 28 students in total.
how many of those 28 fulfill our desired criteria (has a brother) ?
well, it is the sum of the column "has a brother", as it does not matter, if there is also a sister or not.
so, it is 4 + 12 = 16
therefore, the probability to pick a student randomly, who has a brother is
16/28 = 4/7 = 0.571428571...
